Answer:
5.22 x 10^5 V
Explanation:
guessed on castle learning and got it right
Answer:
They had the same speed.
Explanation:
It won't be velocity, because velocity is a vector quantity. Speed is scalar.
Answer:
The ball was in air for 3.896 s
Explanation:
given,
g = 9.8 m/s², acceleration due to gravity,
If the launch angle is 45°, the horizontal range will be maximum.
The horizontal and vertical launch velocities are equal, and each is equal to
v_h = v cos θ
v_h = 27 × cos 45°
= 19.09 m/s.
The time to attain maximum height is one half of the time of flight.
v = u + at ∵ v = 0 (max. height)
19.09 - 9.8 t₁ = 0
t₁ = 1.948 s
The time of flight is twice of the maximum height time
2 t₁ = 3.896 s
The horizontal distance traveled is
D = v × t
D = 3.896×19.09
= 74.375 m
The ball was in air for 3.896 s
To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.
The expression that defines the linear momentum is expressed as
P=mv
Where,
m=mass
v= velocity
According to our data we have to
v=10m/s
d=0.05m

Volume 
t = 3hours=10800s

From the given data we can calculate the volume of rain for 5 seconds

Where,
It is the period of time we want to calculate total rainfall, that is


Through water density we can now calculate the mass that fell during the 5 seconds:



Now applying the prevailing equation given we have to



Therefore the momentum of the rain that falls in five seconds is 