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Butoxors [25]
2 years ago
5

Caelyn wanted to find out what shampoo made her hair the shiniest . Everyday she washed her hair with different shampoos and the

n rated how shiny her hair was, on a scale from 1-10. She used Pantene, Herbal Essences, L’Oreal, and just water
Physics
1 answer:
Arte-miy333 [17]2 years ago
8 0

Answer:

IV: type of shampoo used

DV: what shampoo made her hair the skinniest

control: water

Constant: rated from scale from 1-10

Explanation:

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A proton starts from rest and gains 8.35 x 10^-14 joule of kinetic energy as it accelerates between points A and B in an electri
antoniya [11.8K]

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5.22 x 10^5 V

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guessed on castle learning and got it right

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1 year ago
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Many birds can attain very high speeds when diving. Using radar, scientists measured the altitude of a barn swallow in a vertica
scoray [572]

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0.109

Explanation:

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2 years ago
One car travels 40. meters due east in 5.0 seconds, and a second car travels 64 meters due west in 8.0 seconds. During their per
KengaRu [80]

Answer:

They had the same speed.

Explanation:

It won't be velocity, because velocity is a vector quantity. Speed is scalar.

5 0
2 years ago
A good quarterback can throw a football at 27 m/s (about 60 mph). If we assume that the ball is caught at the same height from w
bezimeni [28]

Answer:

The ball was in air for 3.896 s

Explanation:

given,

g = 9.8 m/s², acceleration due to gravity,

If the launch angle is 45°, the horizontal range will be maximum.

The horizontal and vertical launch velocities are equal, and each is equal to

v_h  =  v cos θ

v_h  =  27 × cos 45°

         = 19.09 m/s.

The time to attain maximum height is one half of the time of flight.

v = u + at                     ∵ v = 0 (max. height)

19.09 - 9.8 t₁ = 0

t₁ = 1.948 s

The time of flight is twice of the maximum height time

2 t₁ = 3.896 s

The horizontal distance traveled is

D = v × t

D = 3.896×19.09

   = 74.375 m

The ball was in air for 3.896 s

8 0
2 years ago
If a rainstorm drops 5 cm of rain over an area of 13 km2 in the period of 3 hours, what is the momentum (in kg · m/s) of the rai
stiks02 [169]

To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.

The expression that defines the linear momentum is expressed as

P=mv

Where,

m=mass

v= velocity

According to our data we have to

v=10m/s

d=0.05m

A=13*10^6m^2

Volume (V) = A*d = (15*10^6)(0.03) = 3.9*10^5m^3

t = 3hours=10800s

\rho = 1000kg/m^3

From the given data we can calculate the volume of rain for 5 seconds

V' = \frac{V}{t}*\Delta t_{total}

Where,

\Delta t_{total} It is the period of time we want to calculate total rainfall, that is

V' = \frac{3.9*10^5}{10800}*5

V' = 1.805*10^2m^3

Through water density we can now calculate the mass that fell during the 5 seconds:

m' = V'*\rho

m' = 1.805*10^2*1000

m' = 1.805*10^5m^2

Now applying the prevailing equation given we have to

P=m'v

P = (1.805*10^5)(10)

P = 1.805*10^6 Kg.m/s

Therefore the momentum of the rain that falls in five seconds is 1.805*10^6 Kg.m/s

4 0
2 years ago
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