Answer:
B) c (the speed of light)
Explanation:
Adding the velocities of the golf ball and the boat is fine in the classical sense.
But the light photons are not bound by the rules of classical dynamics.
Einstein postulated that the speed of light is constant in every frame of reference, irrespective of the speed of the observer. It is the maximum velocity at which an object can move.
So the laser would appear to move at the speed of light for an observer inside the Hermes spacecraft and to the observer on mars.
It is because, inside the Hermes time will be slowed down to make sure nothing moves faster than light. This is called time dilation
let be the time measured inside Hermes,
Time outside Hermes
So 1 second inside Hermes is as long as 1.005 seconds outside Hermes, so the laser would appear to travel at the speed of light to observers outside and inside Hermes.
Answer:
The magnitude of the torque on the loop due to the magnetic field is .
Explanation:
Given that,
Diameter = 10 cm
Current = 0.20 A
Magnetic field = 0.30 T
Unit vector
We need to calculate the torque on the loop
Using formula of torque
Where, N = number of turns
A = area
I = current
B = magnetic field
Put the value into the formula
Hence, The magnitude of the torque on the loop due to the magnetic field is .
Answer:
Distance between peak height (vertically) of projectile and mountain height = (2975.2 - 1800) = 1175.2 m
Distance between where the projectile lands and ship B = (3188.8 - 3110) = 8.8 m
Explanation:
Given the velocity and angle of shot of the projectile, one can calculate the range and maximum height attained by the projectile.
H = (v₀² Sin²θ)/2g
v₀ = initial velocity of projectile = 2.50 × 10² m/s = 250 m/s
θ = 75°, g = 9.8 m/s²
H = 250² (Sin² 75)/(2 × 9.8) = 2975.2 m
Range of projectile
R = v₀² (sin2θ)/g
R = 250² (sin2×75)/9.8
R = 250² (sin 150)/9.8 = 3188.8 m
Height of mountain = 1.80 × 10³ = 1800 m
Maximum height of projectile = 2975.2 m
Distance between peak height (vertically) of projectile and mountain height = 2975.2 - 1800 = 1175.2 m
Distance of ship B from ship A = 2.5 × 10³ + 6.1 × 10² = 2500 + 610 = 3110 m
Range of projectile = 3188.8 m
Distance between where the projectile lands and ship B = 3188.8 - 3110 = 8.8 m
Complete Question
Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at sea level. One container is in Denver at an altitude of about 6,000 ft and the other is in New Orleans (at sea level). The surface area of the container lid is A=0.0155 m. The air pressure in Denver is PD = 79000 Pa. and in New Orleans is PNo = 100250 Pa. Assume the lid is weightless.
Part (a) Write an expression for the force FNo required to remove the container lid in New Orleans.
Part (b) Calculate the force FNo required to lift off the container lid in New Orleans, in newtons.
Part (c) Calculate the force Fp required to lift off the container lid in Denver, in newtons.
Part (d) is more force required to lift the lid in Denver (higher altitude, lower pressure) or New Orleans (lower altitude, higher pressure)?
Answer:
a
The expression is
b
c
d
From the value obtained we can say the that the force required to open the lid is higher at Denver
Explanation:
The altitude of container in Denver is
The surface area of the container lid is
The altitude of container in New Orleans is sea-level
The air pressure in Denver is
The air pressure in new Orleans is
Generally force is mathematically represented as
So we are told the pressure inside is is half the pressure the at sea level so the the pressure acting on the container would
The pressure at sea level is a constant with a value of
So the which is the difference in pressure within and outside the container is
Therefore
Now substituting values
The force to remove the lid in Denver is
So we are told the pressure inside is is half the pressure the at sea level so the the pressure acting on the container would
The pressure at sea level is a constant with a value of
At sea level the air pressure in Denver is mathematically represented as
=>
Let height at sea level is h = 1
The air pressure at height
=>
Equating the both
Substituting value
So
=>
So
Answer with Explanation:
We are given that
Charge on proton,q=
a.We have to find the electric potential of the proton at the position of the electron.
We know that the electric potential
Where
B.Potential energy of electron,U=
Where
Charge on electron
=Charge on proton
Using the formula