There is no picture given so I can't be really sure what color of the cable you're referring to. However, the only relationship I can think of when the power and the current is given would be: P=IV or P = I²R, where P is power, I is current, V is voltage and R is resistance. Solving both equations:
120 W = (24 A)(Voltage)
Voltage = 5 V
120 W = (24 A)²(R)
R = 0.2083 Ω
So, i think the cable would have specification of 5 Volts and 0.2083 ohms.
Answer:
a = 15.1 g
Explanation:
The relation between mass and acceleration is given by :
If a₁ = 0.80g, m₁ = 1510 kg, m₂ = 80 kg, we need to find a₂
So,
So, the car's acceleration would be 15.1 g.
Answer:
88.3
Explanation:
Emf in a rotating coil is given by rate of change of flux:
E= dФ/dt=(NABcos∅)/ dt
N: number of turns in the coil= 80
A: area of the coil= 0.25×0.40= 0.1
B: magnetic field strength= 1.1
Ф: angle of rotation= 90- 37= 53
dt= 0.06s
E= (80 × 0.4× 0.25×1.10 × cos53)/0.06= 88.3V
Using the following formulas for projectile motion:
Height, H = ( Vo^2 * sin theta^2 )/g
Range, R = ( Vo^2 * sin 2*theta )/g
Rearranging in terms of Vo^2:
Vo^2 = gH / sin theta^2
Vo^2 = gR / sin 2*theta
Equating the two formulas to each other to solve for the angle theta:
gR / sin 2*theta = <span>gH / sin theta^2
</span>
Substituting the given values:
(9.8)(111) / sin 2*theta = (9.8)(72.3)<span> / sin theta^2
</span>angle = 52.36 degrees
Therefore, the angle of launch is approximately 52.36 degrees.
