An owl has a mass of 4.00 kg. It dives to catch a mouse, losing 800.00 J of its GPE. What was the starting height of the owl, in
1 answer:
You might be interested in
Answer:
The airplane should release the parcel m before reaching the island
Explanation:
The height of the plane is , and its speed is v=150 m/s
When an object moves horizontally in free air (no friction), the equation for the y measured with respect to ground is
[1]
And the distance X is
x = V.t [2]
Being t the time elapsed since the release of the parcel
If we isolate t from the equation [1] and replace it in equation [2] we get
Using the given values:
x = m
Answer:
B. i=2.79A
C. F=0.066N
Explanation:
A) By the right hand rule we have that
F=iL x B
F=iLBsin(α)
If the wire jump toward the observer the top pole face is the magnetic southpole.
B) The diameter of the pole face is 15cm. We can take this value as L (the length in which the wire perceives the magnetic field). Hence, we have
C) Now the length of the wire that feels B is
and the force will be (by taking the degrees between the magnetic field vector and current vector as 80°)
I hope this is useful for you
regards
Answer:
The <em>correct</em> statements are:
- <em>A. The electric field is nonuniform.</em>
- <em>D. Charge Q is positive.</em>
- <em>E. If charge A moves toward charge Q, it must be a negative charge</em>
Explanation:
The answer choices are:
- A. The electric field is nonuniform.
- B. The electric field is uniform.
- C. Charge Q is negative.
- D. Charge Q is positive.
- E. If charge A moves toward charge Q, it must be a negative charge.
- F. If charge A moves toward charge Q, it must be a positive charge.
The <em>electric field</em> is the electrostatic force per unit of charge,
around around a charge, where another charge would experience the electrostatic force.
The electric field lines are shown in a diagram with arrows ditributed radially away from a positive charge and radially toward a negative charge.
Since the arrows are away from Q, Q is a positive charge: <em>statement D.</em>
Since the size of the arrows decreases as you move away from Q the stregth of the field is not uniform: <em>statement A.</em>
Since the charge Q is positive, a negative charge would be attracted toward it: <em>statement E.</em>