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Neporo4naja [7]
2 years ago
6

Ashley made a paper boat and attached paperclips to the edges. In order to control her boat she used a horseshoe magnet. How is

Ashley able to control her boat without touching it?
A) The boat is moving with currents in the water.
B) The boat is attracted to the magnet by the force of gravity.
C) The boat is attracted to the magnet by the force of magnetism.
D) Ashley would not be able to do this without touching the boat.
Physics
2 answers:
arlik [135]2 years ago
8 0

The true answer is C.

The boat is attracted to the magnet by the force of magnetism.

Let me explain. If Ashley made the paper boat and place it on the water, gravity will try to pull the boat down, however no magnets are used in this situation.

Now if magnets are used in this situation and the paper clip is attach to the boat, rather than gravity pulling it down, the magnet will be pulling paper clip, causing the boat to move, so instead of gravity, it's magnetism.

Note: Magnets=Magnetism

saw5 [17]2 years ago
8 0

Answer:

The answer is C

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Answer:

(a) x=ASin(ωt+Ф₀)=±(√3)A/2

(b) x=±(√2)A/2

Explanation:

For part (a)

V=AωCos(ωt+Ф₀)⇒±0.5Aω=AωCos(ωt+Ф₀)

Cos(ωt+Ф₀)=±0.5⇒ωt+Ф₀=π/3,2π/3,4π/3,5π/3

x=ASin(ωt+Ф₀)=±(√3)A/2

For part(b)

U=0.5E and U+K=E→K=0.5E

E=K(Max)

(1/2)mv²=(0.5)(1/2)m(Vmax)²

V=±(√2)Vmax/2→ωt+Ф₀=π/4,3π/4,7π/4

x=±(√2)A/2

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2 years ago
A hydraulic lift raises a 2000 kg automobile when a 500 N force is applied to the smaller piston. If the smaller piston has an a
Inga [223]

Answer:

The cross-sectional area of the larger piston is 392cm ^{2}[/tex]

Explanation:

To solve this problem we apply the following formula:

Pascal principle: F=P*A   Formula (1)

F=Force applied to the piston

P: Pressure

A= Piston area

Nomenclature:

Fp= Force on the primary piston= 500N

W= car weight =m*g=2000kg*9.8m/s2= 19600N

Fs= Force on the secondary piston= W = 19600N

Ap= Primary piston area=10cm^{2} =10*10^{-4}m^{2}

As= Secondary piston area=?

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

In the equation (1)

P=F/A

Pp=Ps

\frac{Fp}{Ap} = \frac{Fs}{As}

As= \frac{Fs*Ap}{Fp}

As=\frac{19600*10*10^{-4} }{500}

As=0.0392m^{2} =0.0392*10^{4}cm^{2}

As=392cm ^{2}

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2 years ago
Alex throws a 0.15-kg rubber ball down onto the floor. The ball’s speed just before impact is 6.5 m/s, and just after is 3.5 m/s
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Answer: Change in ball's momentum is 1.5 kg-m/s.

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We need to find the change in the magnitude of the ball's momentum. It is given by :

So, the change in the ball's momentum is 1.5 kg-m/s. Hence, this is the required solution.

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7 0
1 year ago
A uniform Rectangular Parallelepiped of mass m and edges a, b, and c is rotating with the constant angular velocity ω around an
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Answer:

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The moment of parallel pipe rotating about it's axis is given by the formula;

I = \frac{M}{3} (a^{2} +b^{2} )   ---------------------------------1

(a) The kinetic energy of a parallel pipe is also given as;

k =\frac{1}{2} Iw^{2} --------------------------------2

Putting equation 1 into equation 2, we have;

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τ = Iw -----------------------3

Putting equation 1 into equation 3, we have

τ = \frac{Mw}{3} (a^{2} +b^{2} )

But

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Equation 4 becomes;

τ = \frac{M}{3} (a^{2} +b^{2} ) ∝

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