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2 years ago

What is the speed of each neutron as they crash together? keep in mind that both neutrons are moving?

Physics

2 answers:

Oksanka [162]2 years ago

8 0

Answer:

The speed, as they crash together, is the same than before the crash, but with opposite directions. In this context, we recur to the collision theory in physics, which says that the amount of movement of each particle before the collision is the same than after the collision, due to the conservation of the amount of movement, which can be described like this: $\Delta p=0$ . This expression means that in a isolated environment (which is present in a neutron's collision), the total amount of movement doesn't change.

Therefore, <em>the speed of neutrons is the same before and after the collision</em>. Specifically the number of this speed depends on the experiment.

Sophie [7]2 years ago

7 0

This involves shooting electrons (from an accelerator) at a target or protons. This technique provided evidence for the existence of quarks. <span>proton-antiproton scattering as well.
</span>hope this helps

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Answer:

I believe the answer for this question is D

Explanation:

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2 years ago

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Consider the vector b⃗ with magnitude 4.00 m at an angle 23.5∘ north of east. what is the x component bx of this vector? express

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2 years ago

A student decides to give his bicycle a tune up. He flips it upside down (so there’s no friction with the ground) and applies a

Alinara [238K]

Answer:

Tangential velocity = 10.9 m/S

Explanation:

As per the data given in the question,

Force = 20 N

Time = 1.2 S

Length = 16.5 cm

Radius = 33.0 cm

Moment of inertia = 1200 kg.cm^2 = 1200 × 10^(-4) kg.m^2

= 1200 × 10^(-2) m^2

Revolution of the pedal ÷ revolution of wheel = 1

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= 3.30 N m

So, Angular acceleration = Torque ÷ Moment of inertia

= 3.30 ÷ 12 × 10^(-2)

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Since wheel started rotating from rest, so initial angular velocity = 0 rad/S

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= 0 + 27.50 × 1.2

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2 years ago

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igor_vitrenko [27]

A lady bug moves 10 cm forward and 5 cm backwards

so total distance moved by lady bug = 10 + 5 = 15 cm

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t = 20 s

so the average speed is given as

$v = \frac{d}{t}$

$v = \frac{15}{20}$

$v = 0.75 cm/s$

so its average speed is 0.75 cm/s

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2 years ago

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