Answer:
The speed, as they crash together, is the same than before the crash, but with opposite directions. In this context, we recur to the collision theory in physics, which says that the amount of movement of each particle before the collision is the same than after the collision, due to the conservation of the amount of movement, which can be described like this: . This expression means that in a isolated environment (which is present in a neutron's collision), the total amount of movement doesn't change.
Therefore, <em>the speed of neutrons is the same before and after the collision</em>. Specifically the number of this speed depends on the experiment.
Answer:
heat required in pan B is more than pan A
Explanation:
Heat required to raise the temperature of the substance is given by the formula
now we know that both pan contains same volume of water while the mass of pan is different
So here heat required to raise the temperature of water in Pan A is given as
Now similarly for other pan we have
So here by comparing the two equations we can say that heat required in pan B is more than pan A
Answer:
Distance between peak height (vertically) of projectile and mountain height = (2975.2 - 1800) = 1175.2 m
Distance between where the projectile lands and ship B = (3188.8 - 3110) = 8.8 m
Explanation:
Given the velocity and angle of shot of the projectile, one can calculate the range and maximum height attained by the projectile.
H = (v₀² Sin²θ)/2g
v₀ = initial velocity of projectile = 2.50 × 10² m/s = 250 m/s
θ = 75°, g = 9.8 m/s²
H = 250² (Sin² 75)/(2 × 9.8) = 2975.2 m
Range of projectile
R = v₀² (sin2θ)/g
R = 250² (sin2×75)/9.8
R = 250² (sin 150)/9.8 = 3188.8 m
Height of mountain = 1.80 × 10³ = 1800 m
Maximum height of projectile = 2975.2 m
Distance between peak height (vertically) of projectile and mountain height = 2975.2 - 1800 = 1175.2 m
Distance of ship B from ship A = 2.5 × 10³ + 6.1 × 10² = 2500 + 610 = 3110 m
Range of projectile = 3188.8 m
Distance between where the projectile lands and ship B = 3188.8 - 3110 = 8.8 m
Explanation:
It is given that,
Mass of the car 1,
Initial speed of car 1, (east)
Mass of the car 2,
Initial speed of car 2, (north)
(b) As the cars stick together. It is a case of inelastic collision. Let V is the common speed after the collision. Using the conservation of momentum as :
The magnitude of speed,
V = 12.22 m/s
(b) Let is the direction the wreckage move just after the collision. It is given by :
Hence, this is the required solution.