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Nina [5.8K]
2 years ago
10

A(n) ________ has charge but negligible mass, whereas a(n) ________ has mass but no charge.

Physics
2 answers:
Dahasolnce [82]2 years ago
7 0

Answer:

An electron has charge but negligible mass, whereas a neutron has mass but no charge.

Explanation:

Atoms are made of equal number of protons and electrons. Almost all the mass of an atom is in the nucleus of the atom. The nucleus is made of protons and neutrons (except hydrogen, which has no neutron)

The charge of an electron is -1.6 \times 10^{-19} C

The charge of a proton is +1.6 \times 10^{-19} C

The charge of a neutron is 0 C

The mass of a proton is 1.6726 \times 10^{-27} kg or 1.007276 u

The mass of a neutron is 1.6749 \times 10^{-27} kg or 1.008664 u

The mass of an electron is 9.1 \times 10^{-31} kg or 0.00054858 u

As we can see the proton is 1,838 times heavier than an electron and the neutron is 1,840 times heavier than an electron.

So the electron has a negligible mass and a negative charge but the neutron has no charge but it is heavier than electron and proton

vfiekz [6]2 years ago
6 0
Electron;Neutron is the correct answer.
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Answer: 14.52*10^6 m/s

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the change in potential energy for the electron; e*ΔV is  equal to energy kinetic gained for the electron so:

e*ΔV=1/2*m*v^2  v^=(2*e*ΔV/m)^1/2= (2*1.6*10^-19*600/9.1*10^-31)^1/2=14.52 *10^6 m/s

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2 years ago
You are on vacation in San Francisco and decide to take a cable car to see the city. A 5800-kgkg cable car goes 260 mm up a hill
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Answer:

4.325\times10^6J

Explanation:

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Therefore the only possible change in the cable car system is the change in it's gravitational potential energy.

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where, g = acceleration due to gravity

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4 0
2 years ago
What is the formula that can be used to find velocity if kinetic energy and mass are known?
viva [34]
The formula for kinetic energy is \frac{1}{2}m\Delta v^2. Thus, the equation for velocity is v=   \sqrt{ \frac{2TotalKineticEnergy}{m} }. 
6 0
2 years ago
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A nonuniform, 80.0-g, meterstick balances when the support is placed at the 51.0-cm mark. At what location on the meterstick sho
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Answer:34 cm

Explanation:

Given

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stick is balanced when support is placed at 51 cm mark

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Answer:

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