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BlackZzzverrR [31]
2 years ago
6

vector A makes equal angles with x,y and z axis. value of its components (in terms of magnitude of vector A will be?

Physics
2 answers:
kiruha [24]2 years ago
5 0
X^2+y^2+z^2=A^2
But here XY and Z are all equal so
3X^2=A^2
X=A/(sqrt(3))
Each component is the value of a divided by the square root of three. This way if you square then and add them up it equals a squared
djverab [1.8K]2 years ago
5 0

Answer:

All three components are

A_x = \frac{A}{\sqrt3}

A_y = \frac{A}{\sqrt3}

A_z = \frac{A}{\sqrt3}

Explanation:

As we know that sum of all three components of the vector will give us resultant vector

So here we can say that

A^2 = A_x^2 + A_y^2 + A_z^2

since it is given that all three components are of same magnitudes so

A_x = A_y = A_z

now we have

A^2 = 3A_x^2

so we have

A_x = A_y = A_z = \frac{A}{\sqrt3}

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At a location where the acceleration due to gravity is 9.807 m/s2, the atmospheric pressure is 9.891 × 104 Pa. A barometer at th
Otrada [13]

Answer:

8616.7468 \ kg/m^3

Explanation:

Pressure is measured is p=\rho gh here p is pressure \rho is density and h is height

We have given pressure p=9.891\times 10^4\ Pa acceleration due to gravity g=9.9870\ m/sec^2 height =1.163 m

\rho =\frac{p}{gh}=\frac{9.891\times 10^4}{9.870\times 1.163}=8616.7468 \ kg/m^3

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2 years ago
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The data table below shows the distribution of the energies of a pendulum 0.60 s into its motion. What is the missing value?
ohaa [14]
The total energy (also called mechanical energy) is the sum of the kinetic energy and potential energy:
TE = KE + PE
For this pendulum, we see that at t=0.60 s the total energy is TE=0.918 J while the potential energy is 0.054 J, so the kinetic energy (the missing value in the table) is
KE=TE-PE=0.918 J - 0.054 J =0.864 J
4 0
1 year ago
Cylinder A is moving downward with a velocity of 3 m/s when the brake is suddenly applied to the drum. Knowing that the cylinder
Xelga [282]

Answer:

Incomplete question

Check attachment for the given diagram

Explanation:

Given that,

Initial Velocity of drum

u=3m/s

Distance travelled before coming to rest is 6m

Since it comes to rest, then, the final velocity is 0m/s

v=3m/s

Using equation of motion to calculate the linear acceleration or tangential acceleration

v²=u²+2as

0²=3²+2×a×6

0=9+12a

12a=-9

Then, a=-9/12

a=-0.75m/s²

The negative sign shows that the cylinder is decelerating.

Then, a=0.75m/s²

So, using the relationship between linear acceleration and angular acceleration.

a=αr

Where

a is linear acceleration

α is angular acceleration

And r is radius

α=a/r

From the diagram r=250mm=0.25m

Then,

α=0.75/0.25

α =3rad/sec²

The angular acceleration is =3rad/s²

b. Time take to come to rest

Using equation of motion

v=u+at

0=3-0.75t

0.75t=3

Then, t=3/0.75

t=4 secs

The time take to come to rest is 4s

7 0
2 years ago
What is the torque τb about axis b due to the force f⃗ ? (b is the point at cartesian coordinates (0,b), located a distance b fr
yKpoI14uk [10]
Check the attached file for the solution.

8 0
2 years ago
A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point
finlep [7]

Answer:

1.17894 m

Explanation:

The rock is at one end of the rod which is 0.211 m from the fulcrum

F = Force

d = Distance

L = Length of rod

M = Mass of rock = 325 kg

g = Acceleration due to gravity = 9.81 m/s²

Torque

\tau=F\times d

Torque of man

\tau_m=F(L-d)\\\Rightarrow \tau_m=695(L-0.211)

Torque of rock

\tau_r=Mg\times d\\\Rightarrow \tau=325\times 9.81\times 0.211\\\Rightarrow \tau=672.72075\ Nm

The torques acting on the system is conserved

\tau_m=\tau_r\\\Rightarrow 695(L-0.211)=672.72075\\\Rightarrow L-0.211=\frac{672.72075}{695}\\\Rightarrow L-0.211=0.96794\\\Rightarrow L=0.96794+0.211\\\Rightarrow L=1.17894\ m

The length of the rod is 1.17894 m

5 0
2 years ago
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