Solution:
Make an Observation - An indoor plant in a dark room withers faster than the same plant in a room with ample sunlight.
Ask a question- Why do certain indoor plants die faster based on where they are placed in the house?
State a hypothesis- Sunlight is probably essential for plants to grow and live.
Run an experiment- Get two potted plants. Cover one with black paper. Place both plants outside in sunlight. See what happens to each plant after one week.
Analyze the results-The plant in the pot with black paper withered. The other plant was healthy.
Communicate the results to others - Plants need sunlight to make food so they can live.
Answer:
Part a)
the tension force is equal to the weight of the crate
Part b)
tension force is more than the weight of the crate while accelerating upwards
tension force is less than the weight of crate if it is accelerating downwards
Explanation:
Part a)
When large crate is suspended at rest or moving with uniform speed then it is given as
here since speed is constant or it is at rest
so we will have
so the tension force is equal to the weight of the crate
Part b)
Now let say the crate is accelerating upwards
now we can say
so tension force is more than the weight of the crate
Now if the crate is accelerating downwards
so tension force is less than the weight of crate if it is accelerating downwards
Answer:
Explanation:
First number is 
Second number is 
We need to multiply the two numbers.
In scientific notation :
Hence, this is the required solution.
This can be answered using trigonometric analysis. This sloped path that is 150 m long is the hypotenuse of the triangle. The adjacent angle would then be 65 degrees. Given these:
sin 65 = h / 150
Where: h = vertical displacement = 150 (sin 65)
h = 135.95 meters
Answer:
E/4
Explanation:
The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:
E = σ/(2ε₀)
Where;
E is the electric field
σ is the surface charge density
ε₀ is the electric constant.
Formula to calculate σ is;
σ = Q/A
Where;
Q is the total charge of the sheet
A is the sheet's area.
We are told the elastic sheet is a square with a side length as d, thus ;
A = d²
So;
σ = Q/d²
Putting Q/d² for σ in the electric field equation to obtain;
E = Q/(2ε₀d²)
Now, we can see that E is inversely proportional to the square of d i.e.
E ∝ 1/d²
The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.
From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;
E_new = E/4
