A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the fo
1 answer:
Answer:
- The period is independent of the suspended mass.
- The period is proportional to the square root of the length of the wire.
Explanation:
A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the following statements are true when the system undergoes small oscillations?
Check all that apply.
A. The period is inversely proportional to the suspended mass.
B. The period is proportional to the square root of the length of the wire.
C. The period is independent of the suspended mass.
D. The period is proportional to the suspended mass.
E. The period is independent of the length of the wire.
F. The period is inversely proportional to the length of the wire.
Simple harmonic motion is periodic motion under the action of a restoring force that is directly proportional to the displacement from equilibrium
from the relation of period T
from the above formula , it can be concluded that
C. The period is independent of the suspended mass
B.The period is proportional to the square root of the length of the wire.
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Answer:
Two possible points
<em>x= 0.67 cm to the right of q1</em>
<em>x= 2 cm to the left of q1</em>
Explanation:
<u>Electrostatic Forces</u>
If two point charges q1 and q2 are at a distance d, there is an electrostatic force between them with magnitude
We need to place a charge q3 someplace between q1 and q2 so the net force on it is zero, thus the force from 1 to 3 (F13) equals to the force from 2 to 3 (F23). The charge q3 is assumed to be placed at a distance x to the right of q1, and (2 cm - x) to the left of q2. Let's compute both forces recalling that q1=1, q2=4q and q3=q.
Equating
Operating and simplifying
To solve for x, we must take square roots in boths sides of the equation. It's very important to recall the square root has two possible signs, because it will lead us to 2 possible answer to the problem.
Assuming the positive sign :
Since x is positive, the charge q3 has zero net force between charges q1 and q2. Now, we set the square root as negative
The negative sign of x means q3 is located to the left of q1 (assumed in the origin).
Answer:
2274 J/kg ∙ K
Explanation:
The complete statement of the question is :
A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.
= mass of metal = 400 g
= specific heat of metal = ?
= initial temperature of metal = 100 °C
= mass of aluminum cup = 100 g
= specific heat of aluminum cup = 900.0 J/kg ∙ K
= initial temperature of aluminum cup = 15 °C
= mass of water = 500 g
= specific heat of water = 4186 J/kg ∙ K
= initial temperature of water = 15 °C
= Final equilibrium temperature = 40 °C
Using conservation of energy
heat lost by metal = heat gained by aluminum cup + heat gained by water