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exis [7]
2 years ago
10

A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the fo

llowing statements are true when the system undergoes small oscillations?
Check all that apply.

A. The period is inversely proportional to the suspended mass.
B. The period is proportional to the square root of the length of the wire.
C. The period is independent of the suspended mass.
D. The period is proportional to the suspended mass.
E. The period is independent of the length of the wire.
F. The period is inversely proportional to the length of the wire.
Physics
1 answer:
jarptica [38.1K]2 years ago
4 0

Answer:

- The period is independent of the suspended mass.

- The period is proportional to the square root of the length of the wire.

Explanation:

A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the following statements are true when the system undergoes small oscillations?

Check all that apply.

A. The period is inversely proportional to the suspended mass.

B. The period is proportional to the square root of the length of the wire.

C. The period is independent of the suspended mass.

D. The period is proportional to the suspended mass.

E. The period is independent of the length of the wire.

F. The period is inversely proportional to the length of the wire.

Simple harmonic motion is periodic motion under the action of a restoring force that is directly proportional to the displacement from equilibrium

from the relation of period T

T=2\pi \sqrt{l/g}

from the above formula , it can be concluded that

C. The period is independent of the suspended mass

B.The period is proportional to the square root of the length of the wire.

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When jumping, a flea accelerates at an astounding 1000 m/s2 but over the very short distance of 0.50 mm. If a flea jumps straigh
Nadusha1986 [10]

Answer:

The flea reaches a height of 51 mm.

Explanation:

Hi there!

The equations of height and velocity of the flea are the following:

During the jump:

h = h0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

While in free fall:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the flea at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

a = acceleration of the flea due to the jump.

v = velocity of the flea at time t.

g = acceleration due to gravity.

First, let's calculate how much time it takes the flea to reach a height of 0.0005 m. With that time, we can calculate the speed reached by the flea during the jump:

h = h0 + v0 · t + 1/2 · a · t²

If we place the origin of the frame of reference on the ground, then, h0 = 0. Since the flea is initially at rest, v0 = 0. Then:

h = 1/2 · a · t²

We have to find the value of t for which h = 0.0005 m:

0.0005 m = 1/2 · 1000 m/s² · t²

0.0005 m / 500 m/s² = t²

t = 0.001 s

Now, let's find the velocity reached in that time:

v = v0 + a · t   (v0 = 0)

v = a · t

v = 1000 m/s² · 0.001 s

v = 1.00 m/s

When the flea is at a height of 0.50 mm, its velocity is 1.00 m/s. This initial velocity will start to decrease due to the downward acceleration of gravity. When the velocity is zero, the flea will be at the maximum height. Using the equation of velocity, let's find the time at which the flea is at the maximum height (v = 0):

v = v0 + g · t

At the maximum height, v = 0:

0 m/s = 1.00 m/s - 9.81 m/s² · t

-1.00 m/s / -9.81 m/s² = t

t = 0.102 s

Now, let's find the height reached by the flea in that time:

h = h0 + v0 · t + 1/2 · g · t²

h = 0.0005 m + 1.00 m/s · 0.102 s - 1/2 · 9.81 m/s² · (0.102 s)²

h = 0.051 m

The flea reaches a height of 51 mm.

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A 1.25 in. by 3 in. rectangular steel bar is used as a diagonal tension member in a bridge truss. the diagonal member is 20 ft l
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Answer:

axial stress in the diagonal bar =36,000 psi

Explanation:

Assuming we have to find axial stress

Given:

width of steel bar: 1.25 in.

height of the steel bar: 3 in

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modulus of elasticity E= 30,000,000 psi

strain in the diagonal member ε = 0.001200 in/in

Therefore, axial stress in the diagonal bar σ = E×ε

=  30,000,000 psi×  0.001200 in/in =36,000 psi

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Answer:

3100 m/s

Explanation:

The relationship between frequency and wavelength of a wave is given by the wave equation:

v=f\lambda

where

v is the speed of the wave

f is its frequency

\lambda is the wavelength

For the wave in this problem,

f = 15,500 Hz

\lambda=0.20 m

Therefore, the wave speed is

v=(15500)(0.20)=3100 m/s

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The scale reading increases by the weight of 200 g of mass. (If you're on Earth, that's about 2 Newtons.)

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