A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the fo
1 answer:
Answer:
- The period is independent of the suspended mass.
- The period is proportional to the square root of the length of the wire.
Explanation:
A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the following statements are true when the system undergoes small oscillations?
Check all that apply.
A. The period is inversely proportional to the suspended mass.
B. The period is proportional to the square root of the length of the wire.
C. The period is independent of the suspended mass.
D. The period is proportional to the suspended mass.
E. The period is independent of the length of the wire.
F. The period is inversely proportional to the length of the wire.
Simple harmonic motion is periodic motion under the action of a restoring force that is directly proportional to the displacement from equilibrium
from the relation of period T
from the above formula , it can be concluded that
C. The period is independent of the suspended mass
B.The period is proportional to the square root of the length of the wire.
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Answer:
The maximum speed of the car at the bottom of that drop is 26.34 m/s.
Explanation:
Given that,
The maximum vertical distance covered by the roller coaster, h = 35.4 m
We need to find the maximum speed of the car at the bottom of that drop. It is a case of conservation of energy. The energy at bottom is equal to the energy at top such that :
v = 26.34 m/s
So, the maximum speed of the car at the bottom of that drop is 26.34 m/s. Hence, this is the required solution.
The resultant static friction force is equal to 20 N to the left.
Why?
I'm assuming that you forgot to write the question of the exercise, so, I will try to complete it:
"A 50-n crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50 . A 20-n force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate?"
So, if we are going to calculate the resulting static friction force, it means that there is no movement, we must remember that the friction coefficient will give us the maximum force before the crate starts to move.
We can calculate the static friction force by using the following formula:
Since the crate is not moving (static), the static friction force acting on the crate will be equal to the applied force.
Calculating we have:
Hence, the static friction force is equal to 20 N to the left (since the applied force is acting to the right)
So,
Since the static friction force is equal to the applied force, the crate does not start to move.
Have a nice day!
Answer:
The ratio is
Explanation:
From the question we are told that
The radius of Phobos orbit is R_2 = 9380 km
The radius of Deimos orbit is
Generally from Kepler's third law
Here M is the mass of Mars which is constant
G is the gravitational constant
So we see that
=>
Here is the period of Deimos
and is the period of Phobos
So
=>
=>