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STALIN [3.7K]
2 years ago
6

A cylindrical flask is fitted with an airtight piston that is free to slide up and down. A mass rests on the top of the piston.

The initial temperature of the system is 313 K and the pressure of the gas is held constant at 137 kPa. The temperature is now increased until the height of the piston rises from 23.4 cm to 27.0 cm.What is the final temperature of the gas?
Physics
1 answer:
butalik [34]2 years ago
3 0

Answer:

T2 = 361.15 K

Explanation:

Since pressure is held constant, then we'll use Charles law

Charles law gives that V1/T1 = V2/T2

We are given;

Initial temperature; T1 = 313 K

Initial height; h1 = 23.4 cm

Final height; h2 = 27.0 cm

Now, formula for volume of a cylinder is V = πr²h

V1 = πr²h1 and V2 = πr²h2

Now, since V1/T1 = V2/T2 and we are looking for T2, let's make T2 subject;

T2 = (V2 × T1)/V1

Plugging in the relevant values gives;

T2 = (πr²h2 × 313)/πr²h1

πr² will cancel out to give;

T2 = (h2 × 313)/h1

Putting 23.4 for h1 and 27 for h2 gives;

T2 = (27 × 313)/23.4

T2 = 361.15 K

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In an experiment, students release a block from rest at the top of an inclined plane. The block slides down the plane through a
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B) Friction

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3. A 75kg man sits at one end of a uniform seesaw pivoted at its center, and his 24kg son sits at the
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Before leaving the house in the morning, you plop some stew in your slow cooker and turn it on Low. The slow cooker has a 160 Oh
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i = \frac{120}{160}

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2 years ago
Sunlight strikes a piece of crown glass at an angle of incidence of 38.0°. Calculate the difference in the angle of refraction b
zhuklara [117]

Answer:

Difference in the angle of refraction = 0.3°

41.04° is the minimum angle of incidence.

Explanation:

Angle of incidence  = 38.0°

For yellow light :

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for yellow light which is 1.523

n₂ is the refractive index of air which is 1

So,  

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{sin\theta_2}=0.9377

Angle of refraction for yellow light = sin⁻¹ 0.9377 = 69.67°.

For green light :

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for green light which is 1.526

n₂ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{38.0}^0}=\frac {1.526}{1}

{sin\theta_2}=0.9395

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The difference in the angle of refraction = 69.97° - 69.67° = 0.3°

Calculation of the critical angle for the yellow light for the total internal reflection to occur :

The formula for the critical angle is:

{sin\theta_{critical}}=\frac {n_r}{n_i}

Where,  

{\theta_{critical}} is the critical angle

n_r is the refractive index of the refractive medium.

n_i is the refractive index of the incident medium.

n₁ is the refractive index for yellow light which is 1.523 (incident medium)  

n₂ is the refractive index of air which is 1 (refractive medium)

Applying in the formula as:

{sin\theta_{critical}}=\frac {1}{1.523}

The critical angle is = sin⁻¹ 0.6566 = 41.04°

5 0
2 years ago
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