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qwelly [4]
2 years ago
14

When were Earth’s landmasses first recognizable as the continents we know today? 10 million years ago 135 million years ago 180

million years ago 300 million years ago
Physics
2 answers:
Bess [88]2 years ago
6 0

Answer:

b

Explanation:

i took the test

cluponka [151]2 years ago
6 0

Answer:

b 135 million years

Explanation:

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20.3 divided by 3.0 will get u velocity and v times 3.0s 
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If a cat falls off a ledge, the Earth pulls the cat to the ground with the force of gravity. According to Newton's Third Law the
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8 0
2 years ago
Read 2 more answers
Electromagnetic radiation is emitted when a charged particle moves through a medium faster than the local speed of light. This r
alexandr1967 [171]

Answer:

to create the particle the speed must be greater than 2.25 10⁸ m / s

Explanation:

In this exercise we must use the relation of the index of refraction with the speed of light in a vacuum and a material medium

           n = c / v

where c is the speed of light in the vacuum, v the speed of light in the material medium and n the ratio of rafraccio

in this case they give us that the medium matter water them that has a refractive index of

              n = 1,333

we clear

          v = c / n

let's calculate

           v = 3 10⁸ / 1,333

           v = 2.25 10⁸ m / s

to create the particle the speed must be greater than 2.25 10⁸ m / s

6 0
2 years ago
A circular pipe of 25-mm outside diameter is placed in an airstream at 25C and 1-atm pressure. The air moves in cross flow over
kifflom [539]

Answer:

f_D = =3.24 N/m

Explanation:

data given

properties of air\nu\ of air =19.31*10^{-6} m2/s

\rho = 1.048 kg/m3

k = 0.0288 W/m.K

WE KNOW THAT

Reynold's number is given as

Re =\frac{VD}{\nu}

      = \frac{ 15*0.025}{19.31*10^{-6}}

      = 1.941 *10^4

drag coffecient is given as

C_D = \frac{f_D}{A_f\frac{\rho v^2}{2}}

solving for f_D

f_D = C_D A_f*\frac{\rho v^2}{2}

     =C_D D*\frac{\rho v^2}{2}

Drag coffecient for smooth circular cylinder is 1.1

therefore Drag force is

f_D = 1.1*0.025 *\frac{1.048*15^2}{2}

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4 0
2 years ago
A bucket of mass M (when empty) initially at rest and containing a mass of water is being pulled up a well by a rope exerting a
Naily [24]

Answer:

V=\dfrac{PT}{m}\ ln\dfrac{M+m}{M}-gT

Explanation:

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V=\dfrac{P}{R}\ ln\dfrac{M+RT}{M}-gT

V=\dfrac{PT}{m}\ ln\dfrac{M+m}{M}-gT

This is the velocity of bucket at the instance when it become empty.

6 0
2 years ago
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