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qwelly [4]
1 year ago
14

When were Earth’s landmasses first recognizable as the continents we know today? 10 million years ago 135 million years ago 180

million years ago 300 million years ago
Physics
2 answers:
Bess [88]1 year ago
6 0

Answer:

b

Explanation:

i took the test

cluponka [151]1 year ago
6 0

Answer:

b 135 million years

Explanation:

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According to Newton's Law of Universal Gravitation, which of the following would cause the attractive force between a planet and
vladimir1956 [14]

Answer:

it is either a or c

Explanation:

4 0
2 years ago
Calculate the energy in the form of heat (in kJ) required to change 75.0 g of liquid water at 27.0 °C to ice at –20.0 °C. Assume
REY [17]

Explanation:

The given data is as follows.

          mass, m = 75 g

      T_{1} = 0^{o}C

      T_{2} = 27^{o}C

      Specific heat of water = 4.18

First, we will calculate the heat required for water is as follows.

            q = m C \times (T_{1} - T_{2})

               = 75 g \times 4.18 J/g^{o}C \times (0 - 27)^{o}C

               = 8464.5 J/mol

               = 8.46 kJ ......... (1)

Also, it is given that T_{3} = -20^{o}C = (20 + 273) K = 293 K and specific heat of ice is 2.108 kJ/kg K.

Now, we will calculate the heat of fusion as follows.

        q = mC \times (T_{3} - T_{1})

           = 0.075 kg \times 2.108 kJ/kg K \times (-293 - 0) K

           = -46.32 kJ ......... (2)

Now, adding both equations (1) and (2) as follows.

               8.46 kJ - 46.32 kJ

             = -37.86 kJ

Therefore, we can conclude that energy in the form of heat (in kJ) required to change 75.0 g of liquid water at 27.0^{o}C to ice at -20.0^{o}C is -37.86 kJ.

4 0
2 years ago
A.Whale communication. Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard n
Y_Kistochka [10]

A. 90.1 m

The wavelength of a wave is given by:

\lambda=\frac{v}{f}

where

v is the speed of the wave

f is its frequency

For the sound emitted by the whale, v = 1531 m/s and f = 17.0 Hz, so the wavelength is

\lambda=\frac{1531 m/s}{17.0 Hz}=90.1 m

B. 102 kHz

We can re-arrange the same equation used previously to solve for the frequency, f:

f=\frac{v}{\lambda}

where for the dolphin:

v = 1531 m/s is the wave speed

\lambda=1.50 cm=0.015 m is the wavelength

Substituting into the equation,

f=\frac{1531 m/s}{0.015 m}=1.02 \cdot 10^5 Hz=102 kHz

C. 13.6 m

Again, the wavelength is given by:

\lambda=\frac{v}{f}

where

v = 340 m/s is the speed of sound in air

f = 25.0 Hz is the frequency of the whistle

Substituting into the equation,

\lambda=\frac{340 m/s}{25.0 Hz}=13.6 m

D. 4.4-8.7 m

Using again the same formula, and using again the speed of sound in air (v=340 m/s), we have:

- Wavelength corresponding to the minimum frequency (f=39.0 Hz):

\lambda=\frac{340 m/s}{39.0 Hz}=8.7 m

- Wavelength corresponding to the maximum frequency (f=78.0 Hz):

\lambda=\frac{340 m/s}{78.0 Hz}=4.4 m

So the range of wavelength is 4.4-8.7 m.

E. 6.2 MHz

In order to have a sharp image, the wavelength of the ultrasound must be 1/4 of the size of the tumor, so

\lambda=\frac{1}{4}(1.00 mm)=0.25 mm=2.5\cdot 10^{-4} m

And since the speed of the sound wave is

v = 1550 m/s

The frequency will be

f=\frac{v}{\lambda}=\frac{1550 m/s}{2.5\cdot 10^{-4} m}=6.2\cdot 10^6 Hz=6.2 MHz

3 0
1 year ago
A plane initially traveling at 200 m/s due west experiences a 10 m/s head wind coming from the opposite direction. A). What will
Hitman42 [59]
Ok so it would be late and the relative velocity would be 190 m/s because 200 m/s - 10 m/s is 190 m/s. Hope this helps.
8 0
2 years ago
If a helicopter's mass is 4,500kg and the net force on it is 18,000 N upward, what is its acceleration?
Vinvika [58]
The acceleration is0.25m/s^2
4 0
1 year ago
Read 2 more answers
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