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denis-greek [22]
2 years ago
14

A pressure cooker is a pot whose lid can be tightly sealed to prevent gas from entering or escaping. even without knowing how bi

g the pressure cooker is, or what altitude it is being used at, we can make predictions about how much force the lid will experience under different conditions.
Physics
1 answer:
ankoles [38]2 years ago
5 0
Even without knowing the size of the pressure cooker or the altitude at which the pressure cooker will be used, we can easily determine the force on the lid by experience because just as boiling water, the amount of pressure inside the vessel (in this case, the cooker) increases as the temperature increases. 
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Aaron Agin nodded off while driving home from play practice this past Sunday evening. His 1500-kg car hit a series of guardrails
Inessa [10]

Answer: 6.48m/s

Explanation:

First, we know that Impulse = change in momentum

Initial velocity, u = 19.8m/s

Let,

Velocity after first collision = x m/s

Velocity after second collision = y m/s

Also, we know that

Impulse = m(v - u). But then, the question said, the guard rail delivered a "resistive" impulse. Thus, our impulse would be m(u - v).

5700 = 1500(19.8 - x)

5700 = 29700 - 1500x

1500x = 29700 - 5700

1500x = 24000

x = 24000/1500

x = 16m/s

Also, at the second guard rail. impulse = ft, so that

Impulse = 79000 * 0.12

Impulse = 9480

This makes us have

Impulse = m(x - y)

9480 = 1500(16 -y)

9480 = 24000 - 1500y

1500y = 24000 - 9480

1500y = 14520

y = 14520 / 1500

y = 9.68

Then, the velocity decreases by 3.2, so that the final velocity of the car is

9.68 - 3.2 = 6.48m/s

5 0
1 year ago
A uniform cube with mass 0.700 kg and volume 0.0270 m3 is sitting on the floor. A uniform sphere with radius 0.400 m and mass 0.
Sav [38]

Answer:

  44 1/3 cm

Explanation:

The cube has an edge length of ∛0.027 m = 0.3 m, so a center of mass (CoM) 15 cm above the floor.

The sphere's center of mass is 40 cm above the top of the cube, so is 70 cm above the floor. The weighted average of the CoM locations is ...

  ((15 cm)(0.700 kg) +(70 cm)(0.800 kg))/(0.700 kg +0.800 kg)

  = (10.5 kg·cm +56 kg·cm)/(1.500 kg) = 44.333... cm

The center of mass of the two-object system is 44 1/3 cm above the floor.

_____

<em>Comment on the units</em>

We're not familiar with "hcm" as a unit. We presume that you can convert the given answer to the units you desire.

6 0
1 year ago
A small sphere with mass 5.00.×10−7kg and charge +3.00μC is released from rest a distance of 0.600 m above a large horizontal in
erma4kov [3.2K]
Given:

m = 5.00x10^-7 kg
q = 3.00<span>μC

To determine the velocity, use this formula
</span>
v = √(2qΔx/m)

Now, solve for the velocity, substitute the given values to the equation

v = √(2(3.00μC * 0.600m/5.00x10^-7 kg)

Solve for V and this is the velocity of your sphere in condition 1. <span />
5 0
2 years ago
Read 2 more answers
Two identical grasshoppers jump into the air with the same initial speed and experience no air resistance. Grasshopper A goes st
avanturin [10]

Answer:

a.) At their highest point, both of them have the same amount of mechanical energy.

Explanation:

Grasshopper A jumps upwards with speed v while grasshopper B jumps at an angle of 66 degree with horizontal at same speed

so vertical speed of B is given

v_y = v sin66 = 0.91v

v_x = v cos66 = 0.41v

So when both the grasshopper will jump upwards they both will attain different maximum heights

Since initial speed of both grasshopper is same so their mechanical energy is always conserved

So mechanical energy of grasshopper A is given as

U = \frac{1}{2}mv^2

Mechanical energy of grasshopper B is given as

U = \frac{1}{2}m(vcos^2\theta) + \frac{1}{2}m(vsin\theta)^2

U = \frac{1}{2}mv^2

So we have

a.) At their highest point, both of them have the same amount of mechanical energy.

7 0
1 year ago
Which model is used to describe the interaction of external forces that affect an organization's strategy and ability to compete
Diano4ka-milaya [45]

Answer:

Competitive forces model

Explanation:

A Competitive forces model is the important tool which is used in the strategic analysis to determine the competitiveness in an organization. The model is commonly known as the "Five Force Model of Porter", which includes five forces — intensity of a rivalry, the bargaining ability of the buyers, threat of the potential new entrants,  the bargaining power of a supplier, and the threat of substitute goods or services.

It affects the organizations's ability to compete as well as the strategy to succeed.

5 0
1 year ago
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