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2 years ago

12

As Aubrey watches this merry-go-round for a total of 2 minutes, she notices the black horse pass by 15 times. What is the period

of the black horse?

2 answers:

marishachu [46]2 years ago

8 0

2 min = 120 sec

120/15 = 8

The black horse represents 8 seconds.

Wewaii [24]2 years ago

5 0

Answer:

8 seconds

Explanation:

The time taken by the merry go round to complete one round is called time period.

Number of rounds = 15

Time taken = 2 minutes = 2 x 60 = 120 second

15 rounds are completetd in 120 seconds

1 round completed in 120 / 15 = 8 seconds

So, the time period is 8 seconds.

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A computer that is 87% efficient consumes 375 kWh of energy. How much useful energy does it provide?

tekilochka [14]

Answer:

326.25 kWh

Explanation:

Efficiency of a machine is defined as the ratio of useful energy to that of the energy consumed by the machine.

Here, efficiency is given as 87% and the energy consumed by the computer is 375 kWh.

Efficiency, $\eta=\frac{\textrm{Useful energy}}{\textrm{Energy consumed}}$

Plug in the values of $\eta=0.87$ and 375 kWh for energy consumed. Solve for useful energy. This gives,

Efficiency, $\eta=\frac{\textrm{Useful energy}}{\textrm{Energy consumed}}\\ 0.87=\frac{\textrm{Useful energy}}{375}\\ \textrm{Useful energy}=0.87\times 375=326.25 \textrm{ kWh}$

Therefore, the useful energy provided by the computer is 326.25 kWh.

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2 years ago

Nora tied a string around a tennis ball, and then she swung it in a circle in front of her to demonstrate a planet orbiting the

777dan777 [17]

<em>Choice-A </em>is a true statement. The string holding the ball in orbit is a contact force, whereas gravity is a non-contact force.

Choice-C is half-true. The string keeps the distance between the bodies constant, but gravity doesn't "MAKE" the distance vary.

8 0

1 year ago

Read 2 more answers

How can promoting total person development can benefit an organization.

Alex787 [66]

Promoting total person development can benefit an organization in the following way

Explanation:

1.Promoting personal development in the workplace

All images courtesy of Forbes Councils members.
Create Growth Plans. ...
Build In 'Growth Time' ...
Set 90-Day Learning Goals. ...
Offer Innovative Learning Experiences. ...
Map Out The Far-Reaching Benefits. ...
Make Development Opportunities 'One Size Fits One' ...
Take An Active Interest In Personal Development. ...
Think Beyond Formal Training.

2. Create a development plan. Help your employees establish goals that are aligned with their strengths, interest and experience, as well as with the overall business strategy. Establish goals and expectations to help them set their sights on career opportunities.

3. 7 Things Every Great Boss Should Do

Acknowledge. When things are going well in your organization, let people know--early and often. ...
Motivate.
Communicate. Communicate clearly, professionally, and often. ...
Trust. Learn to trust your employees. ...
Develop. Set up your employees for success, not failure. ...
Direct.
Partner.

4.Human relations skills such as communication and handling conflict can help us create better relationships. ... Since many companies' organizational structures depend upon people working together, positive human relations skills reduce conflict in the workplace, thereby making the workplace more productive.

5.Improves effectiveness in business

In business, personal development improves effectiveness. It empowers staff to produce better results and meet their targets. For excellent results, an employer or a business owner must have an energetic and a productive team.

5 0

2 years ago

Read 2 more answers

A hobby rocket reaches a height of 72.3 meters and lands 111 meters from the launch point

faust18 [17]

Using the following formulas for projectile motion:

Height, H = ( Vo^2 * sin theta^2 )/g

Range, R = ( Vo^2 * sin 2*theta )/g

Rearranging in terms of Vo^2:

Vo^2 = gH / sin theta^2

Vo^2 = gR / sin 2*theta

Equating the two formulas to each other to solve for the angle theta:

gR / sin 2*theta = <span>gH / sin theta^2
</span>
Substituting the given values:

(9.8)(111) / sin 2*theta = (9.8)(72.3)<span> / sin theta^2
</span>angle = 52.36 degrees

Therefore, the angle of launch is approximately 52.36 degrees.

8 0

2 years ago

Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands,

Elenna [48]

Let $u$ be the initial velocity of the soccer ball at an angle of inclination of $\theta_0$ with the positive x-axis.

Given that:

$\theta_0=45^{\circ}$

The horizontal distance covered by the projectile=20 m

Time of flight, $t_f=2$ seconds

Acceleration due to gravity, $g= 10 m/s^2$ downward.

As "north" and "up" as the positive x ‑ and y ‑directions, respectively.

So, $g= -10 m/s^2$

As the acceleration due to gravity is in the vertical direction, so the horizontal component of the initial velocity remains unchanged.

The x-component of the initial velocity, $u_x=u\cos\theta_0$ .

The horizontal distance covered by the projectile $= u_x\times t_f$

$\Rightarrow u_x\times t_f=20$

$\Rightarrow u_x\times 2=20$

$\Rightarrow u_x=10$ m/s

So, the horizontal component of the velocity is 10 m/s which is constant and the graph has been shown in the figure (i).

Now, $u\cos(45^{\circ})=10$ [as $u_x=u\cos\theta_0$ ]

$\Rightarrow u=10\sqrt{2}$ m/s.

The vertical component of the initial velocity,

$u_y= u\sin\theta_0$

$\Rightarrow u_y=10\sqrt{2}\sin(45^{\circ})$

$\Rightarrow u_y=10$ m/s

Let v be the vertical component of the velocity at any time instant t.

From the equation of motion,

$v=u+at$

where u: initial velocity, v: final velocity, a: constant acceleration, and t: time taken to change the velocity from u to v.

In this case, we have $u=u_y, a= -10 m/s^2$ .

So at any time instant, t.

$v=u_y+(-10)t$

$\Rightarrow v=10-10t$

The vertical component of the velocity, v, is the function of time and related as $v=10-10t$ .

This is a linear equation.

At 2 second, the vertical component of the velocity

v=10-10x2=-10 m/s.

The graph has been shown in figure (ii).

7 0

2 years ago