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sertanlavr [38]
1 year ago
10

One component of a metal sculpture consists of a solid cube with an edge of length 38.9 cm. The alloy used to make the cube has

a density of 7.15 x10^3 kg/m3. Find the cube's mass.
Physics
1 answer:
vovangra [49]1 year ago
7 0

Answer:

The mass of the cube is 420.8 kg.

Explanation:

Given that,

Length of edge = 38.9 cm

Density \rho= 7.15 \times10^{3}\ kg/m^3

We need to calculate the volume of cube

Using formula of volume

V = 38.9^3

V=0.058863\ m^3

We need to calculate the mass of the cube

Using formula of density

\rho = \dfrac{m}{V}

m = V\times\rho

m =0.058863\times7.15 \times10^{3}

m=420.8\ kg

Hence, The mass of the cube is 420.8 kg.

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When the voltage and current have _____ polarities in a pure capacitive circuit, the capacitor is discharging and the energy is
tangare [24]

Answer:opposite

Explanation:for a capacitor to discharge (after charging) the polarities of the current and voltage have to be reversed

6 0
1 year ago
Charge q1 is distance s from the negative plate of a parallel-plate capacitor. Charge q2=q1/3 is distance 2s from the negative p
Svetlanka [38]

Answer:

The ratio (U₁/U₂) = 6

Explanation:

U, the potential energy is given as

U = kqQ/r

k = Coulomb's constant

q = charge we're concerned about

Q = charge of the negative plate of the capacitor

r = distance of q from the negative plate of the capacitor.

For charge q₁

U₁ = kq₁Q/s

U₂ = kq₂Q/2s

But q₂ = q₁/3

U₂ becomes U₂ = kq₁Q/6s

U₁ = kq₁Q/s

U₂ = kq₁Q/6s

(U₁/U₂) = 6

5 0
2 years ago
At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to
mote1985 [20]

Answer:

Ok, the question is incomplete buy ill try to answer this in a general way.

Suppose that you have no-polarized light.

When that light hits one polaroid, the light becomes polarized along some line, and has an intensity I0.

Now, when polarized light hits a polaroid which axis is at an angle θ with respect to the polarization of the light, the intensity of the resulting beam is given by the Malus's law:

I(θ) = I0*cos^2(θ)

For example, if the axis of the polaroid is exactly the same as the one of the polarized light, then we have θ = 0°

and:

I(0°) = I0*cos^2(0°) = I0

So the intensity does not change.

Now, knowing the initial intensity, you can find the angle needed to get a given intensity.

For example, if the question was:

"At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to A"

We should solve:

I(θ) = A = I0*cos^2(θ)

(A/i0) = cos^2(θ)

√(A/I0) = cos(θ)

Acos(√(A/I0)) = θ

6 0
1 year ago
A fisherman casts his bait toward the river at an angle of 25° above the horizontal. As the line unravels, he notices that the b
Butoxors [25]

Answer:

v_{o}=18m/s

Explanation:

According to the exercise we know the angle which the bait was released and its maximum height

\beta =25\\y=2.9m

To find the initial y-component of velocity we need to do the following steps:

v_{y}^{2} =v_{oy}^{2}+2g(y-y_{o})

At maximum height the y-component of velocity is 0 and from the exercise we know that the initial y position is 0

0=v_{oy}^{2}-2(9.8m/s^2)(2.9m)

v_{oy}=\sqrt{2(9.8m/s^{2} )(2.9m)} =7.53m/s

Since the bait is released at 25º

v_{oy}=v_{o}sin(25)

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6 0
1 year ago
Study the diagram and calculate the effort required to balance the load​
Lisa [10]

Answer:

Solution given;

load =600N

effort=?

load distance: 0.6m

effort distance;2.6m

we have

load *load distance :effort *effort distance

0.6*600=effort *2.6

360/2.6=effort

effort:138.46N

<u>R</u><u>e</u><u>q</u><u>u</u><u>i</u><u>r</u><u>e</u><u>d</u><u> </u><u>e</u><u>f</u><u>f</u><u>o</u><u>r</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>1</u><u>3</u><u>8</u><u>.</u><u>5</u><u>N</u><u>.</u>

6 0
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