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scZoUnD [109]
2 years ago
11

The velocity versus time graph of particle A is tangent to the velocity versus time graph for particle B at point O. What is the

acceleration of the particle A at point O?

Physics
1 answer:
lara [203]2 years ago
7 0
As velocities are tangent, the value of both Particle A and Particle B would be same for that point O (Intersecting point)

a = v / t
Here, v = 7, t = 6
So, a = 7/6
a = 1.17 
As the graph is decreasing, value of acceleration would be negative.
So, a = -1.17 m/s²

In short, Your Answer would be Option C

Hope this helps!
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A rocket starts from rest and moves upward from the surface of the earth. For the first 10.0 s of its motion, the vertical accel
Mazyrski [523]
a = 2.7t 
v =  \int\limits^t_0 {2.7t} \, dt =  \frac{2.7}{2} t^2 
x =  \int\limits^t_0 {\frac{2.7}{2} t^2} \, dt =  \frac{2.7}{6} t^3

Solve for v with x = 325.
5 0
2 years ago
Read 2 more answers
The brake in most cars makes use of a hydraulic system. This system consists of a fluid filled tube connected at each end to a p
Maksim231197 [3]

Answer:

The force at the brake pad = 250 N

Explanation:

The hydraulic brake system works on the Pascal's Principle for pressure transmission in fluids; the pressure applied to a fluid is transmitted undiminished in all directions.

For hydraulic systems, the pressure applied to the brake pedal is transmitted undiminished through the fluid filled tube, connected at each end to a piston, to the brake pad.

Hence, mathematically,

P(brake pedal) = P(break pad)

Pressure is given as the force applied divided by the cross sectional Area perpendicular to the direction of applied force.

P(brake pedal) = (Force applied on the brake pedal) ÷ (Cross Sectional Area of the brake pedal)

Force applied on the brake pedal = 50 N

Cross Sectional Area of the brake pedal = 3 cm²

P(brake pedal) = (50/3) = 16.67 N/cm²

P(brake pad) = P(brake pedal) = 16.67 N/cm²

P(brake pad) = (Force applied on the brake pad) ÷ (Cross Sectional Area of the brake pad)

Force applied on the brake pad = F = ?

Cross Sectional Area of the brake pad = 15 cm²

16.67 = (F/15)

F = 16.67 × 15 = 250 N

Hence, the force at the brake pad = 250 N

Hope this Helps!!!

7 0
2 years ago
In which of the following color gradient types does the linear gradient gets mirrored on either side of the starting point?
Travka [436]

Answer: Reflected  

Explanation: Color Gradient refers to the variety of position dependent (as the vary with position) colors which are used to fill a region. Gradient is a mixture of two or more colors. This blend of colors adds depth to the design.

Types of color gradient are

  • Linear: The color blends in a straight from starting to ending point
  • Radial: The color transitions from starting point to ending a circular pattern.
  • Angle: It glides counterclockwise around starting point.
  • Diamond: It makes a diamond shape from starting point and its ending point is one corner of diamond.
  • Reflected: In this color gradient type symmetric linear gradient gets mirrored on either side of the starting point. This type of color gradient can be used to depict a lead pipe.

4 0
2 years ago
An inventor claims to have developed a power cycle having a thermal efficiency of 40%, while operating between hot and cold rese
lesya [120]

From Carnot's theorem, for any engine working between these two temperatures:


efficiency <= (1-tc/th) * 100


Given: tc = 300k (from question assuming it is not 5300 as it seems)

For a, th = 900k, efficiency = (1-300/900) = 70%

For b, th = 500k, efficiency = (1-300/500) = 40% 

For c, th = 375k, efficiency = (1-300/375) = 20% 


Hence in case of a and b, efficiency claimed is lesser than efficiency calculated, which is valid case and in case of c, however efficiency claimed is greater which is invalid. 

7 0
2 years ago
If 56 grams of carbon monoxide burns in oxygen to produce 88 grams of carbon dioxide, the mass of oxygen involved in the reactio
pentagon [3]

Answer : The mass of oxygen involved in the reaction is, 32 grams.

Explanation : Given,

Mass of carbon monoxide = 56 g

Mass of carbon dioxide = 88 g

Molar mass of carbon monoxide (CO) = 28 g/mole

Molar mass of oxygen (O_2) = 32 g/mole

First we have to calculate the moles of carbon monoxide.

\text{Moles of CO}=\frac{\text{Mass of CO}}{\text{Molar mass of CO}}=\frac{56g}{28g/mole}=2moles

Now we have to calculate the moles of oxygen gas.

The balanced chemical reaction will be,

2CO+O_2\rightarrow 3CO_2

From the balanced chemical reaction, we conclude that

2 moles of CO react with 1 mole of O_2

So, the moles of O_2 = 1 mole

Now we have to calculate the mass of oxygen.

\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2

\text{Mass of }O_2=1mole\times 32g/mole=32g

Therefore, the mass of oxygen involved in the reaction is, 32 grams.

5 0
2 years ago
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