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Serjik [45]
2 years ago
15

What differentiates baseline activities from health-enhancing activities?

Physics
2 answers:
gizmo_the_mogwai [7]2 years ago
8 0
The main difference between baseline activities and health-enhancing activities is that baseline activities maintain the status quo, while health-enhancing activities make things better.
earnstyle [38]2 years ago
8 0

Answer:

The difference between reference activities and activities that improve health is the intensity of each one.

Explanation:

Hello! Let's solve this!

Reference activities are activities that do not improve health and have low intensity. For example, walk slowly or stand.

On the other hand, activities that improve health are high intensity activities.

The difference between reference activities and activities that improve health is the intensity of each one.

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A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back
VMariaS [17]

Answer:

Hence, work done= 287.54 J

Explanation:

Given data:

angle of ramp with the ground θ =20°

force applied = 76 N

work done on the crate to slide down 4 m down the ramp

W= F×d cosθ ( only the cos component of the force will slide the crate down)

W= 76×4×cos20= 287.54 J

4 0
2 years ago
You and your surfing buddy are waiting to catch a wave a few hundred meters off the beach. The waves are conveniently sinusoidal
bekas [8.4K]

Answer:

(a): The frequency of the waves is f= 0.16 Hz

Explanation:

T/4= 1.5 s

T= 6 sec

f= 1/T

f= 0.16 Hz (a)

6 0
2 years ago
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The magnetic field at the earth's surface can vary in response to solar activity. During one intense solar storm, the vertical c
Flauer [41]

Answer:

EMF = 33880 Volts

Explanation:

As per Faraday's law of Electromagnetic induction we know that

Rate of change in magnetic flux will induce EMF in the closed conducting loop

so we have

\phi = B.A

now we have

A = (110 \times 10^3)(110 \times 10^3)

A = 1.21 \times 10^{10}

now we have

\phi = B(1.21 \times 10^{10})

now the induced EMF through this loop is given as

EMF = (\frac{dB}{dt})(1.21 \times 10^{10})

EMF = (2.8 \times 10^{-6})(1.21 \times 10^{10})

EMF = 33880 Volts

5 0
2 years ago
1. Which of the following regarding a collision is/are true? a. If you triple your speed your force of impact will be three time
34kurt

Answer:

c

Explanation:

If you double your speed, the energy dissipated in a crash is four times greater

Because impact increases with square of increase in speed.

7 0
2 years ago
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On a cold winter day when the temperature is −20∘C, what amount of heat is needed to warm to body temperature (37 ∘C) the 0.50 L
vlabodo [156]

Answer:

75.6J

Explanation:

Hi!

To solve this problem we must use the first law of thermodynamics that states that the heat required to heat the air is the difference between the energy levels of the air when it enters and when it leaves the body,

Given the above we have the following equation.

Q=(m)(h2)-(m)(h1)

where

m=mass=1.3×10−3kg.

h2= entalpy at 37C

h1= entalpy at -20C

Q=m(h2-h1)

remember that the enthalpy differences for the air can approximate the specific heat multiplied by the temperature difference

Q=mCp(T2-T1)

Cp= specific heat of air = 1020 J/kg⋅K

Q=(1.3×10−3)(1020)(37-(-20))=75.6J

4 0
2 years ago
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