Let A be the last two digits and let B be the sum of the last three digits of your 8-digit student ID. (Example: For 20245347, A
1 answer:
Answer:
The speed is 173 m/s.
Explanation:
Given that,
A = 47
B = 14
Length 1 urk = 58.0 m
An hour is divided into 125 time units named dorts.
3600 s = 125 dots
dorts = 28.8 s
Speed v= (25.0+A+B) urks/dort
We need to convert the speed into meters per second
Put the value of A and B into the speed
Hence, The speed is 173 m/s.
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Answer:
times
Explanation:
First of all, we need to write both the age of the universe and the lifetime of the top quark in scientific notation.
Age of the universe:
(1 followed by 17 zeroes)
Lifetime of the top quark:
(we moved the decimal point 24 places to the right)
Therefore, to answer the question, we have to calculate the ratio between the age of the universe and the lifetime of the top quark:
Answer:
The magnitudes of the net magnetic fields at points A and B is 2.66 x T
Explanation:
Given information :
The current of each wires, I = 4.7 A
dH = 0.19 m
dV = 0.41 m
The magnetic of straight-current wire :
B= μI/2πr
where
B = magnetic field (T)
μ = 1.26 x
(N/
)
I = Current (A)
r = radius (m)
the magnetic field at points A and B is the same because both of wires have the same distance. Based on the right-hand rule, the net magnetic field of A and B is canceled each other (or substracted). Thus,
BH = μI/2πr
= (1.26 x )(4.7)/(2π)(0.19)
= 4.96 x T
BV = μI/2πr
= (1.26 x )(4.7)/(2π)(0.41)
= 2.3 x T
hence,
the net magnetic field = BH - BV
= 4.96 x - 2.3 x
= 2.66 x T
Answer:
The resistance of the axon is .
Explanation:
Given that,
Inner diameter of the model of an axon,
Radius of the model,
Resistivity of the fluid inside the tube wall,
Length of the axon, l = 2 mm = 0.002 m
We know that the resistance in terms of resistivity of an object is given by :
So, the resistance of the axon is . Hence, this is the required solution.