All categories

2 years ago

A badminton player shuffles his shoes in resins explain the scientific reason behind this

Physics

1 answer:

Kobotan [32]2 years ago

4 0

Answer:

To avoid slipping while playing badminton or to increase friction between the shoes and the badminton court or to enhance the grip.

Explanation:

As the question is general so I will try answer it generally.

As badminton court is usually slippery and flat with no or very little friction and while playing badminton, players have to move very fast from place to place.

So, in order to effectively move faster to take the difficult shots with accuracy badminton players increase the friction between their shoes and the badminton court by shuffling resin to their shoes. It helps to enhance the grip.

You might be interested in

A child tugs on a rope attached to a 0.62-kg toy with a horizontal force

Katarina [22]

Answer:

$a=0.8\ m/s^2$

Explanation:

Given that,

Mass of a toy, m = 0.62 kg

Horizontal force, F = 16.3 N

Force on the opposite direction, F' = 15.8 N

We need to find the acceleration of the toy.

Here, two forces are acting in opposite direction, the net force will be the difference of forces.

Net force = 16.3 N-15.8 N

=0.5 N

The formula for net force is given by :

F = ma

a is the acceleration of the toy

$a=\dfrac{F}{m}\\\\a=\dfrac{0.5\ N}{0.62\ kg}\\\\a=0.8\ m/s^2$

So, the acceleration of the toy is $0.8\ m/s^2$ .

6 0

2 years ago

Suppose astronomers discover a new planet farther away from the Sun than Earth. How would the day and year of this planet compar

posledela

I think the answer would be C. because the orbit around the sun compared to the Earth's (Identifies the seasons change and the year) would be longer, but the day is unknown because that is where it would come down to the total mass of the planet and other important factors about the planets properties.

6 0

2 years ago

Read 2 more answers

Using the superposition method, calculate the current through R5 in Figure 8-71

Vladimir79 [104]

by superposition method we can find current in R5

here first let say only 2V battery is present in the circuit

now the equivalent resistance to be found for which we can say

2.2 k ohm and 1 k ohm is connected in parallel

$r_1 = \frac{2.2 * 1}{2.2 + 1}$

$r_1 = 0.6875 k ohm$

now it is in series with 1 k ohm and then that part is in parallel with 2.2 k ohm

$r_2 = \frac{2.2* (1+0.6875)}{2.2 + (1+0.6875)}$

$r_2 = 0.95 k ohm$

now the current flowing through the battery is

$i = \frac{2}{1 + 0.95} = 1.02 mA$

now this will divide into R3 and R2 so current flowing in R3 will be

$i_1 = \frac{2.2}{2.2+1.6875}*1.02 = 0.58 mA$

now this will again divide in R4 and R5

so current in R5 will be

$i_5 = \frac{R_4}{R_4 + R_5}* i_1$

$i_5 = 0.18 mA$

now when only 3 V battery is present in the circuit

R1 and R2 is in parallel and then it is in series with R3

so parallel combination will be

$r_1 = \frac{1*2.2}{2.2 +1} = 0.6875k ohm$

also after its series with R3

$r_2 = 1 + 0.6875 = 1.6875 k ohm$

now it is in parallel with R5 on other side

$r_3 = \frac{1.6875 * 2.2}{1.6875 + 2.2} = 0.95 k ohm$

now current through the battery will be given as

$i = \frac{3}{1 + 0.95} = 1.53 mA$

now it is divide in r2 and R5

so current in R5 is given as

$i_5 = \frac{r_2}{r_2 + R_5}*i$

$i_5 = \frac{1.6875}{2.2 + 1.6875} * 1.53$

$i_5 = 0.67 mA$

now the total current in R5 will be given by super position which is

$i = 0.67 + 0.18 = 0.85 mA$

so there is 0.85 mA current through R5 resistance

5 0

2 years ago

The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 8.9 km. Assume the

exis [7]

Answer:

113.7

Explanation:

maximum distance (s) = 8.9 km

reference intensity (I0) = 1 x 10^{-12} W/m^{2}

power of a juvenile howler monkey (p) = 63 x 10^{-6} W

distance (r) = 210 m

intensity (I) = power/area

where we assume the area of a sphere due to the uniformity of the output in all directions

area = 4π $r^{2}$ = 4π x $210^{2}$ = 554,176.9 m^{2}

intensity (I) = $\frac{63 x 10^{-6} }{554,176.9} = 113.7 x 10^{-12}$

therefore the desired ratio I/I0 = $\frac{113.7 x 10^{-12}}{1 x 10^{-12}}$ = 113.7

7 0

2 years ago

Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless sur

d1i1m1o1n [39]

Answer:

The speed of bullet and wooden bock coupled together, V = 22.22 m/s

Explanation:

Given that,

Mass of the bullet, m = 0.04 Kg

Mass of the wooden block, M = 0.5 Kg

The initial velocity of the bullet, u = 300 m/s

The initial velocity of the wooden block, U = 0 m/s

The final velocity of the bullet and wooden bock coupled together, V = 0 m/s

According to the conservation of linear momentum, the total momentum of the body after impact is equal to the total momentum before impact.

Therefore,

mV + MV = mu + MU

V(m+M) = mu

V = mu/(m+M)

Substituting the values in the above equation,

V = 0.04 Kg x 300 m/s / (0.04 Kg+ 0.5 Kg)

= 22.22 m/s

Hence, the speed of bullet and wooden bock coupled together, V = 22.22 m/s

8 0

2 years ago

A badminton player shuffles his shoes in resins explain the scientific reason behind this​

A badminton player shuffles his shoes in resins explain the scientific reason behind this