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sweet [91]
2 years ago
13

In which case does viscosity play a dominant role? Case A: a typical bacterium (size ~ 1 mm1 mm and velocity ~ 20 mm/s20 mm/s) i

n fresh water. Case B: a swimmer (size ~ 1.5 m1.5 m and velocity ~ 3 m/s3 m/s) in fresh water. Or same for both?
Physics
1 answer:
My name is Ann [436]2 years ago
5 0

Answer:

Case A

Explanation:

given,

size of bacteria = 1 mm x 1 mm

velocity = 20 mm/s

size of the swimmer = 1.5 m x 1.5 m

velocity of swimmer = 3 m/s

Viscous force

F = \eta A \dfrac{dv}{dx}

for the bacteria

F = \eta \times 10^{-6}\times 20\times 10^{-3}

F =2\times 10^{-8} \eta\ N

for the swimmer

F = \eta \times 1.5^2\times 3

F =6.75 \eta\ N

from the above force calculation

In case B inertial force that represent mass is more than the inertial force in case of bacteria.

Viscous force is dominant in case of bacteria.

So, In Case A viscous force will be dominant.

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A majorette in the Rose Bowl Parade tosses a baton into the air with an initial angular velocity of 2.5 rev/s. If the baton unde
oksian1 [2.3K]

Answer:

14 rev

Explanation:

w_{o} = initial angular velocity = 2.5 revs⁻¹

w = final angular velocity = 0.8 revs⁻¹

\alpha = Angular acceleration = - 0.2 revs⁻²

\theta = Angular displacement

Using the equation

w^{2} = w_{o}^{2} + 2 \alpha \theta\\0.8^{2} = 2.5^{2} + 2 (- 0.2) \theta\\ \theta = 14 rev

So the number of revolutions are 14

4 0
2 years ago
An astronaut takes what he measures to be a 10-min nap in a space station orbiting Earth at 8000 m/s. A signal is sent from the
svet-max [94.6K]

Answer:

longer than

Explanation:

given,

time of nap = 10 min

speed of orbiting earth = 8000 m/s

c is the speed of light

using the equation of time dilation

t' = \dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}

now inserting all the values

t' = \dfrac{10}{\sqrt{1-\dfrac{8000^2}{3\times 10^8)^2}}}

t' = \dfrac{10}{0.9999}

t' = 10.001 s

on solving the above equation we will get a value greater than 10minutes.

hence, On earth time of nap measured will be longer than 10 min

3 0
2 years ago
An object moving at a constant velocity travels 274 m in 23 s. what is its velocity?
svetlana [45]
V= 274 meters / 23 sec

V= 11.91 meters per sec
6 0
2 years ago
Read 2 more answers
01 – (Valor – 2,0) O maior campo de testes de veículos da América Latina, localizado na cidade de Indaiatuba (SP), tem forma cir
Scilla [17]

Answer:

a) Calcule a frequência em RPM

= 0.6 RPM

b) a velocidade escalar do carro em m/s.

= 20m/s

Explanation:

a) Calcule a frequência em RPM

A fórmula para calcular a frequência é: 1/T

onde T= Tempo (seconds)

T = 100s

A frequência = 1/100s

A frequência = 0.01Hz

em RPM

A fórmula para calcular a frequência em RPM =

1 Hz = 60RPM

0.01Hz =

A frequência em RPM = 0.01Hz × 60

= 0.6 RPM

b) a velocidade escalar do carro em m/s.

A fórmula para calcular a velocidade escalar = diâmetro ou distância (m) ÷ tempo (s)

Diâmetro ou Distância = 2.0km

Converter 2.0km para m

1 km = 1000m

2km =

2 km × 1000m

= 2000m

A velocidade escalar = 2000m ÷ 100s

A velocidade escalar = 20m/s

Answer:

a) Frequency in RPM

= 0.6 RPM

b) Scalar Velocity

= 20m/s

Explanation:

a) Frequently in RPM

Formula : 1/T

Where T= Time (seconds)

T = 100s

= 1/100s

= 0.01Hz

Frequency in RPM =

1 Hz = 60RPM

0.01Hz = 0.01Hz × 60

= 0.6 RPM

b) Scalar velocity

The formula = Diameter or Distance ÷ Time

Diameter or Distance = 2.0km

Convert 2.0km to m

1 km = 1000m

2km =

2 km × 1000m

= 2000m

Scalar Velocity = 2000m ÷ 100s

Scalar Velocity = 20m/s

8 0
2 years ago
A gas laser has a cavity length of 1/3 m and a single oscillation frequency of 9.0 x 1014 Hz. What is the cavity mode number?
Eddi Din [679]

Answer:

2 × 10⁶

Explanation:

Data provided in the question:

Cavity length, L = \frac{1}{3}m

Oscillation frequency, f_m = 9.0 × 10¹⁴ Hz

Now,

we know,

f_m=\frac{c}{\lambda_m}

here,

c is the speed of light = 3 × 10⁸ m/s

\lambda_m = Wavelength of mode m inside the laser cavity

m is the cavity mode number

Thus,

9.0\times10^{14}=\frac{3\times10^8}{\lambda_m}

or

\lambda_m = \frac{1}{3} × 10⁻⁶

Also,

m\lambda_m = 2L

Therefore,

m × \frac{1}{3} × 10⁻⁶ = 2 × \frac{1}{3}

or

m = 2 × 10⁶

5 0
2 years ago
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