Ask question

Ask question

All categories

1 year ago

15

A floating ice block is pushed through a displacement d = (14 m) i hat - (11 m) j along a straight embankment by rushing water,

which exerts a force F = (158 N) i hat - (179 N) j on the block. How much work does the force do on the block during the displacement?

1 answer:

Alika [10]1 year ago

7 0

Explanation:

Given that,

Displacement in ice block, $d=14i-11j$

Force exerted by water, $F=158i-179j$

To find,

Work done by the force during the displacement.

Solve,

We know that the product of force and displacement is called work done. It is also equal to the dot product of force and displacement as :

$W=F.d$

$W=(158i-179j).(14i-11j)$

We know that, i.i = j.j = k.k = 1

$W=2212+1969=4181\ J$

So, the work done by the force on the block during the displacement is 4181 Joules.

You might be interested in

A box with a mass of 12.5 kg sits on the floor. how high would you need to lift it for it to have a gpe of 355 j

grandymaker [24]

Gpe=mgh

355=12.5×10×h
h=355/125= 2.84m

3 0

2 years ago

A proton and an electron are held in place on the x axis. The proton is at x = -d, while the electron is at x = +d. They are rel

Over [174]

The protons and electrons are held in place on the x axis.
The proton is at x = -d and the electron is at x = +d. They are released at the same time and the only force that affects movement is the electrostatic force that is applied on both subatomic particles. According to Newton's third law, the force Fpe exerted on protons by the electron is opposite in magnitude and direction to the force Fep exerted on the electron by the proton. That is, Fpe = - Fep. According to Newton's second law, this equation can be written as
Mp * ap = -Me * ae
where Mp and Me are the masses, and ap and ae are the accelerations of the proton and the electron, respectively. Since the mass of the electron is much smaller than the mass of the proton, in order for the equation above to hold, the acceleration of the electron at that moment must be considerably larger than the acceleration of the proton at that moment. Since electrons have much greater acceleration than protons, they achieve a faster rate than protons and therefore first reach the origin.

6 0

2 years ago

Solenoid 2 has twice the diameter, twice the length, and twice as many turns as solenoid 1. How does the field B2 at the center

klemol [59]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is option 3

Explanation:

From the question we are told that

The diameter of solenoid 1 is $d_1$

The length of solenoid 1 is $L_1$

The number of turns of solenoid is $N_1$

The diameter of solenoid 2 is $d_2 = 2d_1$

The length of solenoid 2 is $L_2 = 2L_1$

The number of turns of solenoid 2 is $N_2 = 2 N_1$

Generally the magnetic in a solenoid is mathematically represented as

$B = \frac{\mu_o * N * I }{L}$

From this equation we see that

$B \ \alpha \ \frac{N}{L}$

$B = C \frac{N}{L}$

Here C stands for constant

=> $C = \frac{B * \frac{L}{N}$

=> $\frac{B_1 * \frac{L_1}{N_1} = \frac{B_2 * \frac{L_2}{N_2}$

=> $\frac{B_1}{B_2 } = \frac{N_1 L _2}{ N_2L_1}$

=> $\frac{B_1}{B_2 } = \frac{N_1 * (2 L_1)}{ (2 N_2)L_1}$

=> $\frac{B_1}{B_2 } = 1$

=> $B_2 = B_1$

4 0

2 years ago

The bird is held in level flight due to the force exerted on it by the air as the bird beats its wings. What is the maximum valu

Cerrena [4.2K]

Answer:

maximumforce is F = mg

Explanation:

For this case we must use Newton's second law,

Σ F = m a

bold indicate vectors, so we will write it in its components x and y

X axis

Fₓ = maₓ

Axis y

Fy - W = m a $a_{y}$

Now let's examine our case, with indicate that the bird is level, the force of the wings can have a measured angle with respect to the x axis, where the vertical component is responsible for the lift, let's use trigonometry to find the components

Cos θ = Fₓ / F

Fₓ = F cos θ

sin θ = Fy / F

Fy = F sin θ

Let's replace and calculate

F sin θ -w = m a

As the bird indicates that leveling at the same height, so the vertical acceleration is zero (ay = 0)

F sin θ = w = mg

The maximum value of this equation occurs when the sin=1, in this case

F = mg

3 0

1 year ago

A can of sardines is made to move along an x axis from x = 0.47 m to x = 1.20 m by a force with a magnitude given by F = exp(–8x

sattari [20]

If the force were constant or increasing, we could guess that the speed of the sardines is increasing. Since the force is decreasing but staying in contact with the can, we know that the can is slowing down, so there must be friction involved.
Work is the integral of (force x distance) over the distance, which is just the area under the distance/force graph.
The integral of exp(-8x) dx that we need is (-1/8)exp(-8x) evaluated from 0.47 to 1.20 .

I get 0.00291 of a Joule ... seems like a very suspicious solution, but for an exponential integral at a cost of 5 measly points, what can you expect. On the other hand, it's not really too unreasonable. The force is only 0.023 Newton at the beginning, and 0.000067 newton at the end, and the distance is only about 0.7 meter, so there certainly isn't a lot of work going on. The main question we're left with after all of this is: Why sardines ? ?

6 0

1 year ago