Answer:
v_f = 17.4 m / s
Explanation:
For this exercise we can use conservation of energy
starting point. On the hill when running out of gas
Em₀ = K + U = ½ m v₀² + m g y₁
final point. Arriving at the gas station
Em_f = K + U = ½ m v_f ² + m g y₂
energy is conserved
Em₀ = Em_f
½ m v₀ ² + m g y₁ = ½ m v_f ² + m g y₂
v_f ² = v₀² + 2g (y₁ -y₂)
we calculate
v_f ² = 20² + 2 9.8 (10 -15)
v_f = √302
v_f = 17.4 m / s
Answer:
Ionizing radiation is radiation with enough energy so that during an interaction with an atom, it can remove tightly bound electrons from the orbit of an atom, causing the atom to become charged or ionized. ... Forms of electromagnetic radiation.
(from google)
thank you :)
Answer:
The answer is 26/98 how i did this is i divided them mulitiplyed well i cant really explain it but im pretty dure its right
Explanation:
Complete question is;
Which of the following can be reduced to a single number in standard form?
A) 3√3 + 5√8
B) 2√5 + 5√45
C) √7 + √9
D) 4√2 + 3√6
Answer:
Only option B) 2√5 + 5√45 can be reduced to a single number
Explanation:
A) For 3√3 + 5√8;
Let's simplify it to get;
3√3 + 5√(4 × 2)
From this, we get;
3√3 + (5 × 2)√2 = 3√3 + 10√2
This is 2 numbers and not a single number. Thus it can't be reduced to a single number in standard form.
B) 2√5 + 5√45
Simplifying to get;
2√5 + 5√(9 × 5)
This gives;
2√5 + (5 × 3)√5 = 2√5 + 15√5
Adding the surds gives;
17√5.
This is a single number and thus can be reduced to a single number
C) For √7 + √9
Simplifying, to get;
√7 + 3.
This is 2 numbers and not a single number. Thus it can't be reduced to a single number in standard form.
D) 4√2 + 3√6
Thus can't be simplified further because both numbers inside the square root don't have factors that are perfect squares.
Thus, it remains 2 numbers and not a single number and can't be reduced to a single number in standard form.
Answer:
Found in the nucleus, Has mass of one amu
