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Sliva [168]
2 years ago
8

A 5.0 kg cannonball is dropped from the top of a tower. It falls for 1.6 seconds before slamming into a sand pile at the base of

the castle. What is the velocity of the cannonball just before it hits the ground ?
Physics
1 answer:
stepan [7]2 years ago
4 0

Answer:

15.7 m/s

Explanation:

The motion of the cannonball is a accelerated motion with constant acceleration g = 9.8 m/s^2 towards the ground (gravitational acceleration). Therefore, the velocity of the ball at time t is given by:

v(t)=u + gt

where

u = 0 is the initial velocity

g = 9.8 m/s^2 is the acceleration

t is the time

If we substitute t=1.6 s into the equation, we find the final velocity of the cannonball:

v(1.6 s)=0+(9.8 m/s^2)(1.6 s)=15.7 m/s

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Answer:

Explanation:

Given that,

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Initial velocity of the body is zero

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Using equation of motion: free fall

H = ut + ½gt²

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Now just substitute the numbers given into the equation.

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A 5.09 × 1014-hertz electromagnetic wave is traveling through a transparent medium. The main factor that determines the speed of
sergiy2304 [10]
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Please see attachment

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A planar loop consisting of four turns of wire, each of which encloses 200 cm2, is oriented perpendicularly to a magnetic field
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Answer:

0.6A

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