A 5.0 kg cannonball is dropped from the top of a tower. It falls for 1.6 seconds before slamming into a sand pile at the base of
1 answer:
Answer:
15.7 m/s
Explanation:
The motion of the cannonball is a accelerated motion with constant acceleration g = 9.8 m/s^2 towards the ground (gravitational acceleration). Therefore, the velocity of the ball at time t is given by:
where
u = 0 is the initial velocity
g = 9.8 m/s^2 is the acceleration
t is the time
If we substitute t=1.6 s into the equation, we find the final velocity of the cannonball:
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a) Magnitude of the electric force:
b) Tension in the string: 0.010 N
Explanation:
a)
When the charged rod is brought near the ball, then the ball remains "suspended" in an inclined position. Therefore, we can analzye the forces acting in two perpendicular directions:
- Along the horizontal direction, we have the electric force , pushing in one direction, and the component of the tension in the string acting in the opposite direction,
, where T is the tension and
is the angle with the vertical
- Along the vertical direction, we have the weight of the ball, , acting downward (where
is the mass of the ball and
is the acceleration due to gravity), and the component of the tension acting in the upward direction,
Therefore, since the ball is in equilibrium, we have the two equations:
By dividing the two equations, we get
an solving for the electric force, we find
b)
The tension in the string can now be found by using either of the two equations above; for instance, by using the equation along the horizontal direction,
Where
is the electric force
is the angle with the vertical
We find the tension in the string:
Learn more about electric force:
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