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Ira Lisetskai [31]
2 years ago
15

A force of 10 newtons toward the right is exerted on a

Physics
1 answer:
weeeeeb [17]2 years ago
6 0

Answer:

Explanation:

coefficient of kinetic friction of wooden floor μ = .4

force of friction = μ R , R is reaction force of floor

R = mg = weight of body

R = 25 N

force of friction = .4 x 25 = 10 N

Net force on the crate = 10 - 10 = zero .

Net force on the body will be nil.

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An athlete is working out in the weight room. He steadily holds 50 kilograms above his head for 10 seconds. Which statement is t
Nataly_w [17]
<span>The athlete is sweating, straining, sweating, trembling and groaning. 
But if he passed high school physics, then he may remember that
'work' in physics means (force) x (distance).  If there's no distance,
then there's no work. 

He realizes that he isn’t doing any work because he's not moving the weight.</span>
4 0
2 years ago
Read 2 more answers
The velocity of a 3.00 kg parti- cle is given by :v = (8.00tiˆ + 3.00t2jˆ) m/s, with time t in seconds. At the instant the net f
FromTheMoon [43]

Answer:

Part a)

Direction of net force is

\theta = 46.7 degree

Part b)

Direction of the velocity is given as

\phi = 27.9 degree

Explanation:

As we know that the velocity of the particle is given as

v = 8.00 t \hat i + 3.00 t^2\hat j

now the acceleration is given as

a = \frac{dv}{dt}

a = 8.00 \hat i + 6.00 t\hat j

now magnitude of net acceleration is given as

a = \sqrt{64 + 36t^2}

F = 3a

35 = 3\sqrt{64 + 36t^2}

t = 1.41 s

Part a)

Now direction of net force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{6t}{8}

tan\theta = \frac{6(1.41)}{8}

\theta = 46.7 degree

Part b)

Direction of the velocity is given as

tan\phi = \frac{v_y}{v_x}

tan\phi = \frac{3.00 t^2}{8.00 t}

tan\phi = \frac{3.00(1.41)}{8.00}

\phi = 27.9 degree

8 0
1 year ago
Describe the distribution of wdiff in terms of its center, shape, and spread, including any plots you use
melisa1 [442]

Answer:

Figure attached

We can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.

Explanation:

We can use the following R code to obtain the data for wdiff:

source("http://www.openintro.org/stat/data/cdc.R")  #obtain the info

nrow(cdc) # number of elements

names(cdc)  # obtain the name for the variable

[1] "genhlth"  "exerany"  "hlthplan" "smoke100" "height"   "weight"   "wtdesire" "age"      

[9] "gender"  

wdiff represent the difference between desired weight (wtdesire) and current weight (weight) and we can obtain the data with the following code:

wdiff <- (cdc$weight-cdc$wtdesire)

And now we can create the histogram with this code

hist(wdiff,xlim =c(-100,150))

> mean(wdiff)

[1] 14.5891

> median(wdiff)

[1] 10

And the result is on the figure attached.

And we can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.

3 0
2 years ago
A 480-kilogram horse runs across a field at a rate of 40 km/hr. What is the magnitude of the horse's momentum?
Andrej [43]
Momentum (p) = mass × velocity

so, 480×40 = 19,200 kg km/hr

so the answer is C !!
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2 years ago
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What best describes myotibrils
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Myofibrils are composed of long proteins such as actin, myosin, and titin, and other proteins that hold them together. These proteins are organized into thin filaments and thick filaments, which repeat along the length of the myofibril in sections called sarcomeres. Muscles contract by sliding the thin (actin) and thick (myosin) filaments along each other.
8 0
2 years ago
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