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2 years ago

A pitcher exerts a force on a baseball that is 30 times the balls weight. How fast is the pitcher accelerating the ball?

Physics

1 answer:

iVinArrow [24]2 years ago

8 0

Answer:

Pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

Explanation:

Force applied on baseball = 30 times weight of the ball.

Weight of ball = mg, where m is the mass of ball and g is acceleration due to gravity value.

We have force applied is also equal to product of mass and acceleration.

F = ma = 30 x mg

a = 30g

So, pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

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A boy drags a suitcase along the ground with a force of 100 N. If the frictional force opposing the motion of the suitcase is 50

stira [4]

Fortunately, 'force' is a vector. So if you know the strength and direction
of each force, you can easily addum up and find the 'resultant' (net) force.

When we talk in vectors, one newton forward is the negative of
one newton backward. Hold that thought, while I slog through
the complete solution of the problem.

(100 N forward) plus (50 N backward)

= (100 N forward) minus (50 N forward)

= 50 N forward .

That's it.
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2 years ago

Last year a baseball player made 63 errors. This year he made 42. What percent decrease was there in the number of errors commit

Crank

Answer:

33.33 %

Explanation:

given,

error last year = 63

error this year = 42

percent decrease in the error = ?

to find the percentage difference in the error formula used is

= $\dfrac{difference}{original}\times 100$

= $\dfrac{63-42}{63}\times 100$

= $\dfrac{21}{63}\times 100$

= 33.33 %

Percentage decrease in the number of error is equal to 33.33%.

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2 years ago

A 20.0 kg curling stone travels 30.0 m along the ice surface. If the frictional force is 10.0 N, the thermal energy produced is

evablogger [386]

The thermal energy is where the work of friction comes from. That is what stops it eventually. In this case a counter force of 10N is applied over the distance of 30.0m. The energy is given by Force*Distance. Here this is 300J. This friction work is the thermal energy.

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2 years ago

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refrigerant 134a enters a compressor operating at steady state as saturated vapor at 0.12 MPa and exits at 1.2 MPa and 70 C at a

Afina-wow [57]

Answer:

the power input to the compressor is 7.19Kw

Explanation:

Hello!

To solve this problem follow the steps below.

1. We will call 1 the refrigerant state at the compressor inlet and 2 at the outlet.

2. We use thermodynamic tables to determine enthalpies in states 1 and 2.

(note: Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)

through prior knowledge of two other properties such as pressure and temperature. )

h1[quality=1, P=0.12Mpa)=237KJ/Kg

h2(P=1.2Mpa, t=70C)=300.6KJ/kg

3. uses the first law of thermodynamics in the compressor that states that the energy that enters a system is the same that must come out

Q=heat=0.32kJ/s

W=power input to the compressor

m=mass flow=0.108kg/S

m(h1)+W=Q+m(h2)

solving for W

W=Q+m(h2-h1)

W=0.32+0.108(300.6-237)=7.19Kw

the power input to the compressor is 7.19Kw

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2 years ago

If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?

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Answer:

2 meters per second²

Explanation:

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