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dusya [7]
2 years ago
14

A 6.5 l sample of nitrogen at 25◦c and 1.5 atm is allowed to expand to 13.0 l. the temperature remains constant. what is the fin

al pressure? 1. 0.75 atm 2. 3.0 atm 3. 0.063 atm 4. 0.38 atm 5. 0.12 atm
Physics
1 answer:
ollegr [7]2 years ago
8 0
Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:
pV=k
which can also be rewritten as
p_1 V_1 = p_2 V_2 (1)
where the labels 1 and 2 mark the initial and final conditions of the gas.

In our problem, p_1 = 1.5 atm, V_1 =6.5 L and V_2 =13.0 L, so the final pressure of the gas can be found by re-arranging eq.(1):
p_2 = p_1  \frac{V_1}{V_2}= (1.5 atm) \frac{6.5 L}{13.0 L}=0.75 atm

Therefore the correct answer is
<span>1. 0.75 atm</span> 
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When a surface is submerged in a fluid, the resultant pressure force on the body acts in what manner? Assume no shear forces are
Alex17521 [72]

Answer:

Perpendicular to the surface of the body.

Explanation:

When a surface is submerged in a fluid the resultant pressure force on the body acts perpendicular to the surface of the body. This is because fluids cannot withstand nor exert sideways forces. One could obtain this analytically considering that the origin of this force comes from the movement of the fluid molecules.

5 0
2 years ago
A particular string resonates in four loops at a frequency of 320 Hz . Name at least three other (smaller) frequencies at which
goldfiish [28.3K]

Answer:

160 Hz  ,  240 Hz  , 400 Hz

Explanation:

Given that

Frequency of forth harmonic is 320 Hz.

Lets take fundamental frequency = f₁

f_1=\dfrac{320}{4}\ Hz

f₁=80 Hz

Frequency of first harmonic = f₂

f₂=2 f₁

f₂ =2 x 80 = 160 Hz

Frequency of second harmonic = f₃

f₃= 3 f₁=3 x 80 = 240 Hz

Frequency of fifth harmonic = f₅

f₅=  5 f₁= 5 x 80 = 400 Hz

Three frequencies are as follows

160 Hz  ,  240 Hz  , 400 Hz

6 0
2 years ago
Your annoying little brother is dropping rocks out of his bedroom window on the 2nd floor. You are on the ground floor and watch
Valentin [98]

Answer:

Too little information, please elaborate

5 0
2 years ago
The gravity tractor is a proposed spacecraft that will fly close to an asteroid whose trajectory threatens to impact the Earth.
Talja [164]

Answer:

F_g=461lb_f

Explanation:

First calculate the mass of the asteroid. To do so, you need to find the volume and know the density of iron.

If r = d/2 = 645ft, then:

V = \frac{4}{3} \pi r^3

V = 1.124*10^{9}ft^3

So

\delta_{iron}=m/V=491lb/ft^3

m=V*\delta=5.519*10^{11}lb

Once you  know both masses, you can calculate the force using Newton's universal law of gravitation:

F_g=G\frac{m_1m_2}{d^2}

Where G is the gravitational constant:

G= 1.068846 * 10^{-9} ft^3 lb^{-1} s^{-2}

F_g=461lb_f

4 0
2 years ago
8) A soccer goal is 2.44 m high. A player kicks the ball at a distance 10.0 m from the goal at an angle of 25.0°. The ball hits
White raven [17]

Answer:

The initial speed of the soccer ball is 16.38 m/s

Explanation:

given;

vertical distance y = 2.44 m

horizontal distance x = 10.0 m

angle of projection θ = 25.0°

Initial velocity has two components, Vₓ and V_y

Vₓ  = V_i cosθ

V_y = V_i sinθ

The horizontal distance = x = Vₓt + ¹/₂ ˣ g ˣ t², but g =0

x = Vₓt =  V_i cosθ *t

10 = V_i cos25 *t

10 = 0.906V_i*t

V_i*t = 10/0.906 = 11.038 m

The vertical distance (g = - g, because it upward motion against gravity)

y = V_y*t -¹/₂ ˣ g ˣ t²

2.44 = (V_i sinθ)t - ¹/₂ ˣ 9.8 ˣ t²

2.44 = (V_i*t)sinθ - ¹/₂ ˣ 9.8 ˣ t²

2.44 = (11.038)sin25° - 4.9t²

2.44 = (11.038)*0.4226 - 4.9t²

2.44 = 4.6647 - 4.9t²

4.9t² = 4.6647 - 2.44 = 2.2247

t² = 2.2247/4.9

t² = 0.454

t = √0.454

t = 0.674 s

Recall that V_i*t = 11.038 m

V_i*0.674 = 11.038 m, solve for V_i

V_i = 11.038/0.674

V_i = 16.38 m/s

Therefore, the initial speed of the soccer ball is 16.38 m/s

6 0
2 years ago
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