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vagabundo [1.1K]

2 years ago

7

A room with dimensions 7.00m×8.00m×2.50m is to be filled with pure oxygen at 22.0∘C and 1.00 atm. The molar mass of oxygen is 32

.0 g/mol.
How many moles noxygen of oxygen are required to fill the room?
What is the mass moxygen of this oxygen?

1 answer:

VashaNatasha [74]2 years ago

3 0

1) 5765 mol

First of all, we need to find the volume of the gas, which corresponds to the volume of the room:

$V=7.00 m\cdot 8.00 m\cdot 2.50 m=140 m^3$

Now we can fidn the number of moles of the gas by using the ideal gas equation:

$pV=nRT$

where

$p=1.00 atm=1.01\cdot 10^5 Pa$ is the gas pressure

$V=140 m^3$ is the gas volume

n is the number of moles

R is the gas constant

$T=22.0^{\circ}+273=295 K$ is the gas temperature

Solving for n,

$n=\frac{pV}{RT}=\frac{(1.01\cdot 10^5 Pa)(140 m^3)}{(8.314 J/molK)(295 K)}=5765 mol$

2) 184 kg

The mass of one mole is equal to the molar mass of the oxygen:

$M_m = 32.0 g/mol$

so if we have n moles, the mass of the n moles will be given by

$m : n = 32.0 g/mol : 1 mol$

since n = 5765 mol, we find

$m=\frac{(5765 mol)(32.0 g/mol)}{1 mol}=1.84\cdot 10^5 g=184 kg$

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In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

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In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

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Hi there!

The total momentum is calculated as the sum of the momenta of the pieces.

The momentum of each piece is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

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The magnitude of the total momentum is calculated as follows:

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The direction of the momentum vector is calculated using trigonometry:

cos θ = px/p

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