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GalinKa [24]
2 years ago
5

Uranus (mass = 8.68 x 1025 kg) and

Physics
1 answer:
Pepsi [2]2 years ago
5 0

Answer:129,398,203.7 m

Explanation:

According to Newton's law of Universal Gravitation, the force F exerted between two bodies of masses M and m and separated by a distance d is equal to the product of their masses and inversely proportional to the square of the distance:  

F=G\frac{Mm}{d^2} (1)

Where:

F=2.28(10)^{19} N is the gravitational force

G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}is the gravitational constant

M=8.68(10)^{25} kg is the mass of Uranus

m=6.59(10)^{19} kg is the mass of Uranu's moon, Mirana

d is the distance between Uranus and its moon

Isolating d:

d=\sqrt{\frac{GMm}{F}} (2)

d=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(8.68(10)^{25} kg)(6.59(10)^{19} kg)}{2.28(10)^{19} N}} (3)

Finally:

d=129,398,203.7 m

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xxMikexx [17]

Answer: 9130 joules

Explanation:

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Time = 11 seconds

Power = 830 watts

Recall that power is the rate of doing work. Thus, power is workdone divided by time taken.

i.e Power = (workdone/time)

830 watts = Workdone / 11 seconds

Workdone = 830 watts x 11 seconds

Workdone = 9130 joules

Thus, 9130 joules of work is required to get the wheelbarrow across the yard.

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2 years ago
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gaseous h2 and br2 are added to an evacuated 1.15L container kept at 298K. The intial partial pressurre of H2(g) is 0.782 atm an
Nastasia [14]

The partial pressures of HBr when the system reaches equilibrium is 2.4 X 10⁻¹¹ atm

<u>Explanation:</u>

H₂ + Br₂ ⇒ 2HBr

PH₂ = 0.782atm

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Kp = (PHBr)²/ (PH₂) (PBr₂) = 1.4 X 10⁻²¹

At equilibrium:

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PH₂ = 0.782 -x

PBr₂ = 0.493 - x

Kp = (2x)^2 / (0.782-x)(0.493-x)

Now, because Kp is very small, x will be very small compared to 0.782 and 0.493.

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x = 1.2X10⁻¹¹

PHBr = 2x = 2.4 X 10⁻¹¹ atm

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2 years ago
An electric drill transfers 200 J of energy into a useful kinetic energy store. It also transfers 44 J of energy by sound and 48
kramer

Answer:

Er = 108 [J]

Explanation:

To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.

200 - 44 - 48 = Er

Where:

Er = remaining energy [J]

Er = 108 [J]

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2 years ago
Two friends, barbara and neil, are out rollerblading. with respect to the ground, barbara is skating due south at a speed of 5.9
Semmy [17]
<span>As seen by Barbara, Neil is traveling at a velocity of 6.1 m/s at and angle of 76.7 degrees north from due west. Let's assume that both Barbara and Neil start out at coordinate (0,0) and skate for exactly 1 second. Where do they end up? Barbara is going due south at 5.9 m/s, so she's at (0,-5.9) Neil is going due west at 1.4 m/s, so he's at (-1.4,0) Now to see Neil's relative motion to Barbara, compute a translation that will place Barbara back at (0,0) and apply that same translation to Neil. Adding (0,5.9) to their coordinates will do this. So the translated coordinates for Neil is now (-1.4, 5.9) and Barbara is at (0,0). The magnitude of Neil's velocity as seen by Barbara is sqrt((-1.4)^2 + 5.9^2) = sqrt(1.96 + 34.81) = sqrt(36.77) = 6.1 m/s The angle of his vector relative to due west will be atan(5.9/1.4) = atan(4.214285714) = 76.7 degrees So as seen by Barbara, Neil is traveling at a velocity of 6.1 m/s at and angle of 76.7 degrees north from due west.</span>
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2 years ago
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alexgriva [62]

As per the question the distance travelled by  a car is 28.4 inch.

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we know that one inch =2.54 centimeter.

Hence 28.4 inch = 2.54  ×28.4 cm

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Hence the multiplication factor is 72.137 cm which will give unit conversion when multiplied with 28.4 inch.

                 

                             


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