Question

Two circular loops are side by side and lie in the xy-plane. A switch is closed, starting a counterclockwise current in the left-hand loop, as viewed from a point on the positive z-axis passing through the center of the loop. Which of the following statements is true of the right-hand loop in a steady-state situation?a. An induced current moves clockwise.
b. The current remains zero.
c. An induced current moves counterclockwise.

Answer 1

Option C

An induced current moves counterclockwise is true of the right-hand loop in a steady-state situation

Explanation:

Lenz's law says that the induced current passes in such a direction that the magnetic field correlated with it performs to oppose the change that offers it. Here the current in the left-hand loop generates positive flux. The magnetic field correlated with it is in a negative direction.

As a consequence, the right-hand loop will ought a dominant-negative flux. The induced current contests this by creating a magnetic field that is along the positive Z direction. So the induced current will be counterclockwise.