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myrzilka [38]
2 years ago
7

Pulling out of a dive, the pilot of an airplane guides his plane into a vertical circle with a radius of 600 m. At the bottom of

the dive, the speed of the airplane is 150 m/s. What is the apparent weight of the 70-kg pilot at that point?
Physics
1 answer:
adoni [48]2 years ago
6 0

Answer:

3311N

Explanation:

r = radius = 600m

V = speed = 150m/s

Mass = weight = 70kg

The weight of pilot when calculated due to circular motion

W = tv

Fv = mv²/r

Fv = 70x150²/600

Fv = 79x22500/600

= 15750000/600

= 2625N

Real Weight of the pilot = m x g

= 70 x 9.8

= 686N

The apparent Weight is calculated by

Mv²/r + mg

= 2625N + 686N

= 3311 N

Therefore the apparent Weight is 3311N

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Answer

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Using energy conservation              

    m g h = \dfrac{1}{2}mv^2

    v= \sqrt{2gh}                  

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A hummingbird can a flutter its wings 4800 times per minute what is the frequency of wing flutters per second
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An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance
bagirrra123 [75]

Answer:

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Now use third law of motion V^{2} = u^{2} - 2 a s

Put all the values in above formula we get,

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Answer:

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