Pulling out of a dive, the pilot of an airplane guides his plane into a vertical circle with a radius of 600 m. At the bottom of
1 answer:
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Answer:
57.94°
Explanation:
we know that the expression of flux
where Ф= flux
E= electric field
S= surface area
θ = angle between the direction of electric field and normal to the surface.
we have Given Ф= 78
E=
S=
=
=0.5306
θ=57.94°
Answer:
The freight train would take 542.265 second to increase the speed of the train from rest to 80.0 kilometers per hour.
Explanation:
Statement is incomplete. Complete description is presented below:
<em>A freight train has a mass of </em><em>. The wheels of the locomotive push back on the tracks with a constant net force of </em>
<em>, so the tracks push forward on the locomotive with a force of the same magnitude. Ignore aerodynamics and friction on the other wheels of the train. How long, in seconds, would it take to increase the speed of the train from rest to 80.0 kilometers per hour?</em>
If locomotive have a constant net force (), measured in newtons, then acceleration (
), measured in meters per square second, must be constant and can be found by the following expression:
(1)
Where is the mass of the freight train, measured in kilograms.
If we know that and
, then the acceleration experimented by the train is:
Now, the time taken to accelerate the freight train from rest (), measured in seconds, is determined by the following formula:
(2)
Where:
- Final speed of the train, measured in meters per second.
- Initial speed of the train, measured in meters per second.
If we know that ,
and
, the time taken by the freight train is:
The freight train would take 542.265 second to increase the speed of the train from rest to 80.0 kilometers per hour.
Answer:
The newton’s second law is F=ma
The Gravitational force is
Explanation:
Given that,
The equivalent formulas for velocity, acceleration, and force using the relationships covered for UCM, Newton’s Laws, and Gravitation.
We know that,
Velocity :
The velocity is equal to the rate of position of the object.
....(I)
Acceleration :
The acceleration is equal to the rate of velocity of the object.
....(II)
Newton’s second Laws
The force is equal to the change in momentum.
In mathematically,
Put the value of p
Put the value from equation (II)
This is newton’s second laws.
Gravitational force :
The force is equal to the product of mass of objects and divided by square of distance.
In mathematically,
Where, m₁₂ = mass of first object
m= mass of second object
r = distance between both objects
Hence, The newton’s second law is F=ma
The Gravitational force is