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Arisa [49]
2 years ago
9

A 50 g tennis ball travels at a velocity of 15 m/s, hits a basketball with a mass of 600 g that is stationary on a frictionless

surface and then rebounds back in the opposite direction with a velocity of -6 m/s . How fast will the basketball be moving after the collision? m/s
Physics
1 answer:
statuscvo [17]2 years ago
8 0

Answer:

1.75 m/s

Explanation:

Momentum is conserved.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(50 g) (15 m/s) + (600 g) (0 m/s) = (50 g) (-6 m/s) + (600 g) v

v = 1.75 m/s

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A body is projected upward at an angle of 30 degree to the horizontal at an initial speed of 200ms-.In how many seconds will it
Crazy boy [7]

Answer:

20.41 s

3534.80 m

Explanation:

<em><u>In how many seconds will it reach the ground?</u></em>

We are given the initial velocity of the body, which is 200 m/s at a 30° angle.

We know the acceleration in the vertical direction is -9.8 m/s², assuming that the upwards/right direction is positive and the downwards/left direction is negative.

Since we are using acceleration in the y-direction, let's use the vertical component of the initial velocity.

  • 200 · sin(30) m/s

Let's use the fact that at the top of its trajectory, the body will have a final velocity of 0 m/s.

Now we have one missing variable that we are trying to solve for: time t.

Find the constant acceleration equation that contains v₀, v, a, and t.

  • v = v₀ + at

Substitute known values into the equation.

  • 0 = 200 · sin(30) + (-9.8)t
  • -200 · sin(30) = -9.8t
  • t = 10.20408163

Recall that this is only half of the body's trajectory, so we need to double the time value we found to find the total time the body is in the air.

  • 2t = 20.40816327

The body will reach the ground in 20.41 seconds.

<em><u>How far from the point of projection would it strike? </u></em>

We want to find the displacement in the x-direction for the body.

Let's find the constant acceleration equation that contains time t, that we just found, and displacement (Δx).

  • Δx = v₀t + 1/2at²

Substitute known values into the equation. Remember that we want to use the horizontal component of the initial velocity and that the acceleration in the x-direction is 0 m/s².

  • Δx = (200 · cos(30) · 20.40816327) + 1/2(0)(20.40816327)²
  • Δx = 3534.797567

The body will strike 3534.80 m from the point of projection.

4 0
1 year ago
Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of m
OverLord2011 [107]

To solve this problem we will start from the definition of energy of a spring mass system based on the simple harmonic movement. Using the relationship of equality and balance between both systems we will find the relationship of the amplitudes in terms of angular velocities. Using the equivalent expressions of angular velocity we will find the final ratio. This is,

The energy of the system having mass m is,

E_m = \frac{1}{2} m\omega_1^2A_1^2

The energy of the system having mass 2m is,

E_{2m} = \frac{1}{2} (2m)\omega_1^2A_1^2

For the two expressions mentioned above remember that the variables mean

m = mass

\omega =Angular velocity

A = Amplitude

The energies of the two system are same then,

E_m = E_{2m}

\frac{1}{2} m\omega_1^2A_1^2=\frac{1}{2} (2m)\omega_1^2A_1^2

\frac{A_1^2}{A_2^2} = \frac{2\omega_2^2}{\omega_1^2}

Remember that

k = m\omega^2 \rightarrow \omega^2 = k/m

Replacing this value we have then

\frac{A_1}{A_2} = \sqrt{\frac{2(k/m_2)}{(k/m_1)^2}}

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m_1}{m_1}}

But the value of the mass was previously given, then

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m}{2m}}

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{1}{2}}

\frac{A_1}{A_2} = 1

Therefore the ratio of the oscillation amplitudes it is the same.

5 0
2 years ago
Your friend Amanda suffers from a condition that reduces her blood's ability to carry oxygen.which of the following is the name
Anestetic [448]
Amanda might be suffering from a disease called Sickle Cell Anemia. It is an inherited red blood cell disorder.
7 0
2 years ago
How much heat Q2Q2 is transferred to the skin by 25.0 gg of steam onto the skin? The heat of vaporization for steam is L=2.256×1
astraxan [27]

Answer:

56400Joules

Explanation:

The quantity of heat required is expressed as;

Q = mL

m is the mass = 25g = 0.025kg

L is the latent heat of vaporization for steam = 2.256×10^6J/kg

Substitute into the formula as shown;

Q = 0.025×2.256×10^6

Q = 56400Joules

Hence the quantity of hear required is 56400Joules

3 0
1 year ago
Paano nakatulong ang estratehikong lokasyon ng Pilipinas sa paghubog ng ating kasayasayan?​
dangina [55]

Answer:

wow sa Canada pa talaga nagtanong btw answer ko ayy

Kasaysayan ng Pilipinas

Kasaysayan ng PilipinasAng Pilipinas ay isang bansa na makikita sa timog-silangang Asya at malapit sa dagat Pasipiko. Ito ay binubuo ng mahigit sa 7000 na isla, at nagsisilbing tirahan para sa mga Pilipino. Ang mga sumusunod ay ilan lamang sa mga paraan kung paanong nakatulong ang estratehikong lokasyon ng ating bansa sa pagbuo ng ating kasaysayan:

Kasaysayan ng PilipinasAng Pilipinas ay isang bansa na makikita sa timog-silangang Asya at malapit sa dagat Pasipiko. Ito ay binubuo ng mahigit sa 7000 na isla, at nagsisilbing tirahan para sa mga Pilipino. Ang mga sumusunod ay ilan lamang sa mga paraan kung paanong nakatulong ang estratehikong lokasyon ng ating bansa sa pagbuo ng ating kasaysayan:Dahil tayo ay napalilibutan ng anyong tubig, pangingisda ang naging pangunahing pamumuhay ng mga sinaunang Pilipino.

mahigit sa 7000 na isla, at nagsisilbing tirahan para sa mga Pilipino. Ang mga sumusunod ay ilan lamang sa mga paraan kung paanong nakatulong ang estratehikong lokasyon ng ating bansa sa pagbuo ng ating kasaysayan:Dahil tayo ay napalilibutan ng anyong tubig, pangingisda ang naging pangunahing pamumuhay ng mga sinaunang Pilipino.Noong naglayag si Ferdinand Magellan, siya ay napunta sa isa sa mga isla sa Pilipinas. Ito ang naging simula ng kolonisasyonDahil sa estratehikonglo

<em> </em>

6 0
1 year ago
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