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iren [92.7K]
2 years ago
13

during a cold winter day, wind at 42 km/h is blowing parallel to a 6-m-high and 10-m-high wall of a house. If the air outside is

at 5 degrees C and the surface temperature of the wall is 12 degrees C, determine the rate of heat loss from that wall by convection. What would your answer be if the wind velocity was doubled?

Physics
1 answer:
Arturiano [62]2 years ago
4 0

Answer: 9.08KW and 16.21KW

Explanation:

The convection over a flat surface with a length of 10 m and a width of 6m.

The mean temperature is (5oC + 12oC)/2 = 8.5oC.

Then find the following properties of air at this temperature from Table A-15:

k = 0.02428 W/m(oC, v= 1.413x10-5 m2/s, and Pr = 0.7340.

find the Reynolds number. Re= VL/v

Check screenshot

This means that the flow becomes turbulent over the plate and we can use the Nusselt number equation for combined laminar and turbulent flow.

Check screenshot

We then use this Nusselt number to find the heat transfer coefficient and the heat transfer.

Check the screen shot for the calculation

Ans

9.08 kW

Then if the wind velocity were doubled, the Re number would be doubled and we would repeat the calculations above, starting with this revised Reynolds number..

Ans

16.21 kW

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Note: The diagram referred to in the question is attached here as a file.

Answer:

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Explanation:

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Were I is the current flowing through the wires

The distance R from point 1 to m is calculated using the pythagora's theorem

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Substituting R into equation (1)

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2 years ago
A baseball catcher puts on an exhibition by catching a 0.15-kg ball dropped from a helicopter at a height of 101 m. What is the
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Answer:

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Hi there!

To solve this problem, let´s use the law of conservation of energy. Since there is no air resistance, the only energies that we should consider is the gravitational potential energy and the kinetic energy. Because of the conservation of energy, the loss of potential energy of the ball must be compensated by a gain in kinetic energy.

In this case, the potential energy is being converted into kinetic energy as the ball falls (this is only true when there are no dissipative forces, like air resistance, acting on the ball). Then, the loss of potential energy (PE) is equal to the increase in kinetic energy (KE):

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-(final PE - initial PE) = final KE - initial KE

The equation of potential energy is the following:

PE = m · g · h

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g = acceleration due to gravity.

h = height.

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

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-(final PE - initial PE) = final KE - initial KE          

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