VO2 max is considered to be the most valid measure<span> of </span>cardio respiratory fitness<span>. It </span>measures<span> the capacity of the heart, lungs, and blood to transport oxygen to the working muscles, and </span>measures<span> the utilization of oxygen by the muscles during exercise.</span>
Answer:
The plate's surface charge density is 
Explanation:
Given that,
Speed = 9800 km/s
Distance d= 75 cm
Distance d' =15 cm
Suppose we determine the plate's surface charge density?
We need to calculate the surface charge density
Using work energy theorem


Here, final velocity is zero
...(I)
We know that,


...(II)
From equation (I) and (II)

Charge is negative for electron

Put the value into the formula


Hence, The plate's surface charge density is 
Starting from the angular velocity, we can calculate the tangential velocity of the stone:

Then we can calculate the angular momentum of the stone about the center of the circle, given by

where
m is the stone mass
v its tangential velocity
r is the radius of the circle, that corresponds to the length of the string.
Substituting the data of the problem, we find
Answer:
No, the velocity of the grocery cart will not remain constant, but instead will increase continuously
Explanation:
No the grocery cart will not move at constant velocity over the spilled maragine because as the frictional force is changed to - 20 N, the net force will not be equal to zero
Net force on the cart when frictional force is changed to - 20 N is 40 - 20 N = 20 N
As the force is positive, it means that the force is acting in the direction of motion of the cart and will increase the velocity of the cart as the force is acting in the direction of motion
∴ The velocity of the cart will not remain constant instead it will increase
Answer:
(a) 160000 kV/m
(b) 1336 keV
Explanation:
(a) magnetic filed, B = 10 T
energy of electron, E = 740 eV
mass of electron, m = 9.1 x 10^-31 kg
Let v be the velocity of electron.
E = 1/2 mv^2
740 x 1.6 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2
v = 1.6 x 10^7 m/s
v = E / B
E = v x B = 1.6 x 10^7 x 10 = 16 x 10^7 V/m
E = 160000 kV/m
(b) E = 16 x 10^7 V/m
B = 10 T
Let v be the velocity of protons.
v = E / B = 16 x 10^7 / 10 = 1.6 x 10^7 m/s
Kinetic energy of proton, E = 1/2 mv^2
= 0.5 x 1.67 x 10^-27 x 1.6 x 1.6 x 10^14
= 2.14 x 10^-13 J = 1336000 eV = 1336 keV