The gravitational potential energy of the brick is 25.6 J
Explanation:
The gravitational potential energy of an object is the energy possessed by the object due to its position in a gravitational field.
Near the surface of a planet, the gravitational potential energy is given by

where
m is the mass of the object
g is the strength of the gravitational field
h is the height of the object relative to the ground
For the brick in this problem, we have:
m = 8 kg is its mass
g = 1.6 N/kg is the strenght of the gravitational field on the moon
h = 2 m is the height above the ground
Substituting, we find:

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<span>The answer should be the vegitation. </span>
Answer:
Output power of the circuit is 3 Watt.
Given:
loss in decibles = 3 dB
Input power = 6 Watt
To find:
Output power = ?
Formula used:
Output power = Input power × loss in ratio
Solution:
3 dB loss = 0.5 ratio
Output power is given by,
Output power = Input power × loss in ratio
Output power = 6 × 0.5
Output power = 3 Watt
Thus, output power of the circuit is 3 Watt.
Would presume you are asked to find the volume, since there is no second volume.
By General Gas Law:
P₁V₁/T₁ = P₂V₂/T₂
1.6 * 168 /255 = 1.3*V₂/285
V₂ = 1.6 * 168 * 285 / (1.3*255)
V₂ = 231.095
Final volume ≈ 231 cm³