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maks197457 [2]
1 year ago
9

Listed following are locations and times at which different phases of the moon are visible from earth’s northern hemisphere. mat

ch these to the appropriate moon phase.
Physics
1 answer:
Airida [17]1 year ago
7 0
For the answer tot he questions above, I know this one.
The answers are
 <span>-sets 2-3 hours after the sun sets - waxing crescent 
-occurs about 3 days before the new moon - waning crescent 
-occurs 14 days after the new moon - full moon 
-rises at about the time the sun sets - full moon 
-visible due south at midnight - full moon 
-visible near eastern horizon just before sunrise waning crescent 
-visible near western horizon about an hour after sunset waxing crescent</span>
You might be interested in
PLEEEEEAAASSSEEE HELP ME
Xelga [282]

Answer:

1) A.  0.44 m/s East + 0.33 m/s North

2) A.  0 m/s²

3) A.  a scalar calculated as distance divided by time.

4) B.  31 km per hour

Explanation:

1) Velocity is DISPLACEMENT over time.

at 1 m/s, total time of walking is 9000 seconds

displacement is 3000 m north and 5000 - 1000 = 4000 m east

4000 m/ 9000 s = 0.44 m/s E

3000 m/ 9000s = 0.33 m/s N

2) constant speed means no acceleration

3) A. a scalar calculated as distance divided by time.

4) displacement 50 km N and 80 km W

v = √(50² + 80²) / (1 + 2) = 31.446603... km/hr

3 0
1 year ago
Un electrón en un tubo de rayos catódicos acelera desde el reposo con una aceleración constante de 5.33x10¹²m/s² durante 0.150μs
Andre45 [30]
Can you translate that in English ? I'll try to help you out with that..
3 0
2 years ago
In an experiment, students release a block from rest at the top of an inclined plane. The block slides down the plane through a
mote1985 [20]

Answer:

B) Friction

Explanation:

The main source of error is the omission of the effect from friction between block and incline, which is directly proportional to the mass of the block. The force of gravity is constant. The friction force dissipates part of the gravitational potential energy, generating a final speed less than calculated under the consideration of a conservative system. Air resistance is neglected at low speeds like this case.

8 0
1 year ago
Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m
Alja [10]

Answer : Zamir's displacement and Talia's displacement is equal.

Explanation :

Displacement is explained to be the changing position of an object.

Zamir covers total distance 27 m and Talia covers total distance 19 m but  Zamir's initial and final position and Talia's initial and final position is same.

So, we can say that Zamir's displacement and Talia's displacement is equal.

6 0
1 year ago
Read 2 more answers
A solid sphere of brass (bulk modulus of 14.0 ✕ 1010 N/m2) with a diameter of 2.20 m is thrown into the ocean. By how much does
astra-53 [7]

Answer:

Diameter decreases by the diameter of 0.0312 m.

Explanation:

Given that,

Bulk modulus =  14.0 × 10¹⁰ N/m²

Diameter d = 2.20 m

Depth = 2.40 km

Pressure = ρ g h = 1030 × 9.81 × 2.4 × 1000

               = 24.25 × 10⁶  N/m²

Volume = \dfrac{4}{3} \pi r^3

         \dfrac{\Delta V}{V}=\dfrac{(\Delta r)^3}{r^3}

Bulk modulus is equal to

B = -\dfrac{\Delta P}{\dfrac{\Delta V}{V} }

now

B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{r^3} }

B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{1.1^3} }

(\Delta r)^3 = \dfrac{24.25 \times 10^6 \times 1.1^3}{14.0 \times 10^{10}}

Δ r = -0.0156 m

change in diameter

Δ d = -2 × 0.0156

Δ d = -0.0312 m

Diameter decreases by the diameter of 0.0312 m.

7 0
1 year ago
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