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emmasim [6.3K]
2 years ago
9

Anna needs to move a box of paperback books across the room. If she applies a force of 20 newtons to the box, what is the magnit

ude of the force exerted by the box on Anna?
Physics
2 answers:
vlabodo [156]2 years ago
5 0
Newton's third law tells us that for every force there is an equal and opposite force.  This means that if Anna exerts a force of 20 Newtons on the box, the box exerts a force of 20 Newtons on Anna.
ycow [4]2 years ago
3 0

Answer:

The magnitude of the force exerted by the box on Anna is 20 newtons.

Explanation:

It is given that, Anna needs to move a box of paperback books across the room. If she applies a force of 20 newtons to the box. We need to find the magnitude of the force exerted by the box on Anna.

The force exerted by the box on Anna is 20 newtons but it acts in the opposite direction as per Newton's third law of motion. The third law of motion explains the impact of forces i.e. action and reaction force.

So, the magnitude of the force exerted by the box on Anna is also 20 newtons. Hence, this is the required solution.

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Summarize two of the most common arguments made by animal rights advocates to support the discontinuation of animals in research
Dvinal [7]
Animal rights<span> is the idea that some, or all, </span>non-human animals<span> are entitled to the possession of their own lives and that their most basic interests—such as the need to avoid </span>suffering—should be afforded the same consideration as similar interests of human beings. <span>They maintain that animals should no longer be viewed as property or used as food, clothing, research subjects, entertainment, or beasts of burden.</span>
3 0
2 years ago
Read 2 more answers
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
Sedaia [141]

Answer:

335°C

Explanation:

Heat gained or lost is:

q = m C ΔT

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

Heat gained by the water = heat lost by the copper

mw Cw ΔTw = mc Cc ΔTc

The water and copper reach the same final temperature, so:

mw Cw (T - Tw) = mc Cc (Tc - T)

Given:

mw = 390 g

Cw = 4.186 J/g/°C

Tw = 22.6°C

mc = 248 g

Cc = 0.386 J/g/°C

T = 39.9°C

Find: Tc

(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)

Tc = 335

7 0
2 years ago
Ice fishermen sit on top of frozen lakes in the winter and catch fish in the liquid water below through holes cut in the ice she
melomori [17]

Answer:

This is because below 4°c, water unlike other materials becomes less dense when it's temperature is further lowered.

Explanation:

Due to the unusual nature of water; at about 4°c, the behavior of the density of water in relation to its temperature reverses. This means that water becomes less dense as it becomes colder below 4°c. The colder parts therefore floats to the top of the water body while the warmer part sinks allowing the top to freeze and the remaining body below to remain in its liquid state.

The freezing of the top of the lake alone protects the remaining depth of water from freezing by acting as an insulator and preventing further heat loss from the water to the ambient space. If this had not been the case, and water froze all through, marine lives will freeze to death and it will be more difficult to melt the ice come the next summer.

This behavior is due to the hydrogen bonding of the water molecules.

8 0
2 years ago
A battleship simultaneously fires two shells toward two identical enemy ships. One shell hits ship A, which is close by, and the
luda_lava [24]

Answer:

both cannonballs hit the ships with the same horizontal speed

Explanation:

Hello!

A parabolic motion is characterized in that its vertical component in Y is constantly changing, this is due to the constant downward acceleration of gravity.

When the movement starts the speed at Y is maximum, then when it reaches its maximum height point its speed is zero, and finally it begins to increase downwards until it touches the floor.

On the other hand, the horizontal speed remains constant AS THERE IS NO ACCELERATION IN HORIZONTAL DIRECTION.

therefore both cannonballs hit the ships with the same horizontal speed

regards!

8 0
2 years ago
A solid steel cylinder is standing (on one of its ends) vertically on the floor. The length of the cylinder is 3.2 m and its rad
maksim [4K]

To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as

\Upsilon = \frac{F/A}{\Delta L/L_0}

Where,

F = Force/Weight

A = Area

\Delta L= Compression

L_0= Original Length

According to the values given we have to

\Upsilon_{steel} = 200*10^9Pa

\Delta L = 5.6*10^{-7}m

L_0 = 3.2m

r= 0.59m \rightarrow A = \pi r^2 = \pi *0.59^2 = 1.0935m^2

Replacing this values at our previous equation we have,

\Upsilon = \frac{F/A}{\Delta L/L_0}

200*10^9 = \frac{F/1.0935}{5.6*10^{-7}/3.2}

F = 38272.5N

Therefore the Weight of the object is 3.82kN

4 0
2 years ago
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