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emmasim [6.3K]
2 years ago
9

Anna needs to move a box of paperback books across the room. If she applies a force of 20 newtons to the box, what is the magnit

ude of the force exerted by the box on Anna?
Physics
2 answers:
vlabodo [156]2 years ago
5 0
Newton's third law tells us that for every force there is an equal and opposite force.  This means that if Anna exerts a force of 20 Newtons on the box, the box exerts a force of 20 Newtons on Anna.
ycow [4]2 years ago
3 0

Answer:

The magnitude of the force exerted by the box on Anna is 20 newtons.

Explanation:

It is given that, Anna needs to move a box of paperback books across the room. If she applies a force of 20 newtons to the box. We need to find the magnitude of the force exerted by the box on Anna.

The force exerted by the box on Anna is 20 newtons but it acts in the opposite direction as per Newton's third law of motion. The third law of motion explains the impact of forces i.e. action and reaction force.

So, the magnitude of the force exerted by the box on Anna is also 20 newtons. Hence, this is the required solution.

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A rock is thrown straight up with an initial velocity of 19.6 m/s. What time interval elapses between the rock’s being thrown an
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Answer:

It will take 4 sec rock to comes its original point

Explanation:

It is given that the rock comes to its original point

So displacement S = 0 m

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According to second equation of motion h=ut+\frac{1}{2}gt^2

0=19.6\times t+\frac{1}{2}\times 9.8t^2

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The drawing shows a person (weight W = 588 N, L1 = 0.838 m, L2 = 0.398 m) doing push-ups. Find the normal force exerted by the f
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Complete Question

The complete question is shown on the first uploaded image

Answer:

Force on each hand is 196.22 N

Force on each foot is 95.8 N

Explanation:

In order to get a better understanding of this question let us explain some concepts

Normal Force:

We can define normal force Fn as that type of force which makes a 90 degree angle with the surface on which it is exerted.

Torque:

We can define torque as the moment of forces that tends to produce or cause rotation

From the question we are given that

Weight of body is (W) = 584 N

The normal force on both hands (Ha) = ?

The normal force on both legs (Lg) = ?

Looking at the diagram the person is at equilibrium so

                 584 = Ha + Lg

an also this mean that torques acting on the body is balanced

         So,   0.410 Ha  = 0.840 Lg

    Making Lg the subject of formula in the equation above we

   Lg = 0.4881 Ha

 Considering the first equation and replacing Lg with this recent equation we have

                      584 = Ha + 0.4881 Ha

          Therefore Ha = 392.44 N

This value obtained is  for both hands for each hand we divide by 2

Therefore we have for each hand = 392.44/2 =196.55 N

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             Lg = 0.4881 ×  392.44

                  = 191.22 N

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                  191.22/2 = 95.8 N.

8 0
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A spring stretches 0.220 m when a 0.400 kg-mass is hung from it. What is its spring constant? (Mass is not a force )
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We want to know the amount of force that stretches the spring 0.22 m.
That force is the WEIGHT of the mass hung from it.
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