An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by
1 answer:
Answer:
W ≈ 5.9 × J
Hence, option (c) is correct.
Given:
mass of box = 6 kg
Displacement of box = 10 m
To find:
Work done by the force = ?
Formula used:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
Solution:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
W = 6 × 9.8 ×10
W = 588 Joule
Thus, W ≈ 5.9 × J
Hence, option (c) is correct.
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Answer:C
Explanation:
It is given that hand strap moves from the vertical in the backward direction.
The direction of strap depends upon the acceleration of bus i.e. if bus is accelerating in forward direction then strap will move in backward direction and vice-versa.
The reason for moving backwards is due to the psuedo acting on strap which bends the strap in backward direction
angle of inclination is given by
where a=acceleration of bus
=inclination of strap from vertical
so we cannot conclude anything about the direction of the velocity of the bus
Answer:
The average rate of energy transfer to the cooker is 1.80 kW.
Explanation:
Given that,
Pressure of boiled water = 300 kPa
Mass of water = 3 kg
Time = 30 min
Dryness friction of water = 0.5
Suppose, what is the average rate of energy transfer to the cooker?
We know that,
The specific enthalpy of evaporate at 300 kPa pressure
We need to calculate the enthalpy of water at initial state
We need to calculate the enthalpy of water at final state
Using formula of enthalpy
Put the value into the formula
We need to calculate the rate of energy transfer to the cooker
Using formula of rate of energy
Put the value into the formula
Hence, The average rate of energy transfer to the cooker is 1.80 kW.
Answer:
Explanation:
Let L be the length of the wire.
velocity of pulse wave v = L / 24.7 x 10⁻³ = 40.48 L m /s
mass per unit length of the wire m = 14.5 x 10⁻⁶ x 10⁻³ / 2 x 10⁻² kg / m
m = 7.25 x 10⁻⁷ kg / m
Tension in the wire = Mg , M is mass hanged from lower end.
= .4 x 9.8
= 3.92 N
expression for velocity of wave in the wire
, T is tension in the wire , m is mass per unit length of wire .
40.48 L =
1638.63 L² = 3.92 / (7.25 x 10⁻⁷)
L² = 3.92 x 10⁷ / (7.25 x 1638.63 )
L² = 3299.64
L = 57.44 m /s