An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by
1 answer:
Answer:
W ≈ 5.9 × J
Hence, option (c) is correct.
Given:
mass of box = 6 kg
Displacement of box = 10 m
To find:
Work done by the force = ?
Formula used:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
Solution:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
W = 6 × 9.8 ×10
W = 588 Joule
Thus, W ≈ 5.9 × J
Hence, option (c) is correct.
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The Torque is defined as,
Where,
I=Inertial Moment
Angular acceleration
Also Torque with linear equation is defined as,
Where,
F = Force
d= distance
Our dates are given as,
R = 30 cm = 0.3m
m = 1.5 kg
F = 20 N
r = 4.0 cm = 0.04 m
t = 4.0s
Therefore matching two equation we have that,
For a wheel the moment inertia is defined as,
I= mR2, replacing we have
Then the velocity of the wheel is
Therefore the correct answer is D.
Answer:
-13.18°C
Explanation:
To develop the problem it is necessary to consider the concepts related to the thermal conduction rate.
Its definition is given by the function
Where,
Q = The amount of heat transferred
t = time
k = Thermal conductivity constant
A = Cross-sectional area
The difference in temperature between one side of the material and the other
d= thickness of the material
The problem says that there is a loss of heat twice that of the initial state, that is
Replacing,
Solvinf for ,
Therefore the temprature at the outside windows furface when the heat lost per second doubles is -13.18°C