An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by
1 answer:
Answer:
W ≈ 5.9 × J
Hence, option (c) is correct.
Given:
mass of box = 6 kg
Displacement of box = 10 m
To find:
Work done by the force = ?
Formula used:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
Solution:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
W = 6 × 9.8 ×10
W = 588 Joule
Thus, W ≈ 5.9 × J
Hence, option (c) is correct.
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<u>Answer:</u>
Cannonball will be in flight before it hits the ground for 2.02 seconds
<u>Explanation:</u>
Initial height from ground = 20 meter.
We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 , we need to calculate time when s = 20 meter.
Substituting
So it will take 2.02 seconds to reach ground.