P = mv
p = 3.5 × 5
p = 17.5 kg .m/s
Hope this helps!
(a) 
The radiation pressure exerted by an electromagnetic wave on a surface that totally absorbs the radiation is given by

where
I is the intensity of the wave
c is the speed of light
In this problem,

and substituting
, we find the radiation pressure

(b) 
Since we know the cross-sectional area of the laser beam:

starting from the radiation pressure found at point (a), we can calculate the force exerted on a tritium atom:

And then, since we know the mass of the atom

we can find the acceleration, by using Newton's second law:

Answer:
q = 4.5 nC
Explanation:
given,
electric field of small charged object, E = 180000 N/C
distance between them, r = 1.5 cm = 0.015 m
using equation of electric field

k = 9 x 10⁹ N.m²/C²
q is the charge of the object

now,

q = 4.5 x 10⁻⁹ C
q = 4.5 nC
the charge on the object is equal to 4.5 nC
Answer:
0.647 nC
Explanation:
The force experienced by a charge due to the presence of an electric field is given by

where
q is the charge
E is the magnitude of the electric field
In this problem, each antenna is modelled as it was a single point charge, experiencing a force of

Therefore, if the electric field magnitude is

Then the charge on each antenna would be

The pet store would be the reference point because it is where he started and it will not move. Hope this helped.