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tatyana61 [14]
2 years ago
7

Consider a very small hole in the bottom of a tank 17.0 cm in diameter filled with water to a heightof 90.0 cm. Find the speed a

t which the water exits the tank through the hole.20)A) 44.1 m/s B) 48.3 m/s C) 4.20 m/s D) 17.64 m/s
Physics
1 answer:
umka21 [38]2 years ago
5 0

Answer:

Speed of water, v = 4.2 m/s

Explanation:

Given that,

Diameter of the tank, d = 17 cm

It is placed at a height of 90 cm, h = 0.9 m

We need to find the speed at which the water exits the tank through the hole. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 0.9}

v = 4.2 m/s

So, the speed of water at which the water exits the tank through the hole is 4.2 m/s. Hence, this is the required solution.

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In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t
mina [271]

Answer:

n = 2.06 moles

Explanation:

The absolute pressure at depth of 27 inches can be calculated by:

Pressure = Pressure read + Zero Gauge pressure

Zero Gauge pressure = 14.7 psi

Pressure read = 480 psi

Total pressure = 480 psi + 14.7 psi = 494.7 psi

P (psi) = 1/14.696  P(atm)

So, Pressure = 33.66 atm

Temperature = 25°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25 + 273.15) K = 298.15 K  

T = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

33.66 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K  

⇒n = 2.06 moles

7 0
2 years ago
3. A 75kg man sits at one end of a uniform seesaw pivoted at its center, and his 24kg son sits at the
bulgar [2K]

Answer:

The wife have to sit at 0.46 L from the middle point of the seesaw.

Explanation:

We need to make a sketch of the seesaw and the loads acting over it.

And by the studying of the Newton's law we can find the equation useful to find the distance of the mother sitting on the seesaw with respect to the center ot the pivot point.

A logical intuition will give us the idea that the mother will be on the side of her son to make the balance.

The maximum momentum with respect to the pivot point (0) will be:

M=75 *\frac{L}{2}

Where L/2 is the half of the distance of the seesaw

Therefore the other loads ( mom + son) must be create a momentum equal to the maximum momentum.

7 0
2 years ago
Small frogs that are good jumpers are capable of remarkable accelerations. One species reaches a takeoff speed of3.7 m/s in60 ms
MAVERICK [17]

We know that acceleration is change in velocity by time taken for that change.

In this case velocity change is 3.7 m/s

Time taken for this change = 60 ms = 6 *10^{-3} seconds

So acceleration of frog  = \frac{3.7}{60*10^{-3}}

                                       = 61.66 m/s^2

So acceleration of frog is 61.66 m/s^2

o it is evident that frog is capable of remarkable accelerations.

8 0
2 years ago
Read 2 more answers
This means that the speed at which the bullet travels across Earth's surface (its magnitude of horizontal velocity) does not aff
Dmitry_Shevchenko [17]

Answer: the speed at which it falls toward the Earth.


Explanation:


A bullet travelling across Earth's surface with some horizontal velocity is classical example of projectile motion.


Projectile motion is an idealization of the motion under the action of gravity neglecting the influence of the air (no drag force nor friction).


This  kind of motion is the result of two independent motions: vertical motion and horizontal motion.


The observed net velocity is the vectorial sum of the vertical and horizontal velocities.


The horizontal velocity is constant, since there is not any force acting in the horizontal axis. Thi is, the object, following the first Law of Newton (inertia law) tends to continue in uniform rectilinear movement (with zero acceleration).


The vertical velocity, this is the velocity at which the bullet falls toward the Earth, is influenced (accelerated) by the action of the gravity of the Earth. So, the vertical velocity is accelerated by the pull of the Earth.


Vertical and horizontal velocities are independent of each other, which means that the speed or the magnitude of the horizontal velocity does not affect the speed at which an object (the bullet) falls toward the Earth.

6 0
2 years ago
An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster. If her velocity increases to 5 m/s, what is
Arturiano [62]
1) The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where m is the object's mass and v its speed.

By using this equation, we find the initial kinetic energy of the skateboarder:
K_i= \frac{1}{2}(80 kg)(3 m/s)^2=360 J
and the final kinetic energy as well:
K_f= \frac{1}{2}(80 kg)(5 m/s)^2=1000 J

So, her change in kinetic energy is
\Delta K=K_f-K_i=1000 J-360 J=640 J

2) The work-energy theorem states that the work done to increase the speed of an object is equal to the variation of kinetic energy of the object:
W=\Delta K
Therefore, the work done by the skateboarder is
W=\Delta K=640 J
7 0
2 years ago
Read 2 more answers
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