Question

Small frogs that are good jumpers are capable of remarkable accelerations. One species reaches a takeoff speed of3.7 m/s in60 ms . Part a what is the frog's acceleration during the jump?

Answer 1

We know that acceleration is change in velocity by time taken for that change.

In this case velocity change is 3.7 m/s

Time taken for this change = 60 ms = $6 *10^{-3} seconds$

So acceleration of frog  = $\frac{3.7}{60*10^{-3}}$

                                       = 61.66 m/$s^2$

So acceleration of frog is 61.66 m/$s^2$

o it is evident that frog is capable of remarkable accelerations.

Answer 2

The frog's acceleration during the jump is 62 m/s²

Further explanation

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

Given:

initial speed = u = 0 m/s

final speed = v = 3.7 m/s

time taken = t = 60 ms = 0.06 s

Unknown:

acceleration = a = ?

Solution:

To find the acceleration of th frog, it can be done in the following way:

$a = \frac{v - u}{t}$

$a = \frac{3.7 - 0}{0.06}$

$a = \frac{185}{3}$

$a \approx 62 ~ m/s^2$

Conclusion:

The frog's acceleration during the jump is 62 m/s²

Learn more

• Velocity of Runner : brainly.com/question/3813437
• Kinetic Energy : brainly.com/question/692781
• Acceleration : brainly.com/question/2283922
• The Speed of Car : brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate, Frog , Jump