The position of an object that is oscillating on an ideal spring is given by the equation x=(12.3cm)cos[(1.26s−1)t]. (a) at time
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Answer:
35,79 meters
Explanation:
So, we got an archer, and we got a target. Lets call the distance between this two d.
Now, the archer fires the arrow, that, in a time travels the distance d with a speed
of 40 m/s and hits the target. We can see that the equation will be:
Immediately after this, the arrow produces a muffled sound, which will travel the distance d at 340 m/s in a time . Obtaining :
.
Finally, the sound reaches the archer, exactly 1 second after he fired the bow, so:
.
This equation allows us to write:
.
Plugging this relationship in the distance equation for the sound:
.
Now, we can replace d from the first equation, and obtain:
.
Now, we can just work a little bit:
.
Now, we can just plug this value into the first equation:
Answer:
Speed of the wave is 7.87 m/s.
Explanation:
It is given that, tapping the surface of a pan of water generates 17.5 waves per second.
We know that the number of waves per second is called the frequency of a wave.
So, f = 17.5 Hz
Wavelength of each wave,
Speed of the wave is given by :
v = 7.87 m/s
So, the speed of the wave is 7.87 m/s. Hence, this is the required solution.