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Nastasia [14]
2 years ago
6

Technician A says that the use of some RTV sealants to seal components on an engine can damage the oxygen sensor. Technician B s

ays that it is common to use a heavy-duty reversible drill to spin the oil pump to pre-lube the engine. Who is correct?a. tech Ab. tech Bc. both A and Bd. neither A nor B
Physics
1 answer:
netineya [11]2 years ago
7 0

Answer: The correct option is C(both A and B)

Explanation:

In engine chambers, internal combustion of fuel is used to produce mechanical energy.

RTV ( Room Temperature Vulcanising) sealants are silicon products used for the sealing purpose of the engine component. As the name implies once exposed to air, it solidifies. However, it has a negative effect on the oxygen sensor of the engine components by makes a coating over the sensors with the silicone film and, after a time, will affect the operation performed by them. Therefore Technician A is correct.

Technician B is equally correct in that an engine need to be lubricated with oil to help cool the moving part while on. But in order to ensure that oil reaches all movable parts a common method know as heavy-duty reversible spin drills is applied. This method regulates the flow of oil using the engine.

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Charge: A piece of plastic has a net charge of +2.00 μC. How many more protons than electrons does this piece of plastic have? (
snow_lady [41]

Answer

given,

net charge = +2.00 μC

we know,

1 coulomb charge =  6.28 x 10¹⁸electrons

1 micro coulomb  charge =  6.28 x 10¹⁸ x 10⁻⁶ electron

                                         = 6.28 x 10¹² electrons

2.00 μC = 2 x 6.28 x 10¹² electrons

              = 1.256 x 10¹³ electrons

since net charge is positive.

The number of protons should be 1.256 x 10¹³ more than electrons.

hence, +2.00 μC have 1.256 x 10¹³ more protons than electrons.

6 0
2 years ago
A measuring cylinder contains 60cm3 of oil at 0 celcius. When a piece of ice was roped into the cylinder it sank completely in o
mariarad [96]

Answer:

S_i=\frac{9}{10} =0.9

Explanation:

Given:

  • volume of oil in the cylinder, V_o=60\ cm^2
  • volume of the oil level when the ice is immersed, V=90\ cm^3
  • the volume level of oil when the ice melted, V'=87\ cm^3

<u>Now, therefore the volume of ice:</u>

V_i=V-V_o

V_i=90-60

V_i=30\ cm^3

<u>Now the volume of water:</u>

V_w=V'-V_o

V_w=87-60

V_w=27\ cm^3

As we know that the relative density is the ratio of density of the substance to the density of water.

<u>So, the relative density of ice:</u>

S_i=\frac{\rho_i}{\rho_w} .....................(1)

as we know that density is given as:

\rm \rho=\frac{mass}{volume}

now eq. (1)

S_i=\frac{m}{V_{i}}\div  \frac{m}{V_w}

where, m = mass of the water or the ice which remains constant in any phase

S_i=\frac{V_w}{V_i}

S_i=\frac{27}{30}

S_i=\frac{9}{10} =0.9

7 0
2 years ago
A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 13.0 cm , giving it a ch
Leokris [45]

a) Electric field inside the paint layer: zero

b) Electric field just outside the paint layer: -3.62\cdot 10^7 N/C

c) Electric field 8.00 cm outside the paint layer: -7.27\cdot 10^7 N/C

Explanation:

a)

We can find the electric field inside the paint layer by applying Gauss Law: the total flux of the electric field through a gaussian surface is equal to the charge contained within the surface divided by the vacuum permittivity, mathematically:

\int EdS = \frac{q}{\epsilon_0}

where

E is the electric field

dS is the element of surface

q is the charge within the gaussian surface

\epsilon_0 = 8.85\cdot 10^{-12}F/m is the vacuum permittivity

Here we want to find the electric field just inside the paint layer, so we take a sphere of radius r as Gaussian surface, where

R = 6.5 cm = 0.065 m is the radius of the plastic sphere (half the diameter)

By taking the sphere of radius r, we note that the net charge inside this sphere is zero, therefore

q=0

So we have

\int E dS=0

which means that the electric field inside the paint layer is zero.

b)

Now we want to find the electric field just outside the paint layer: therefore, we take a Gaussian sphere of radius

r=R=0.065 m

The area of the surface is

A=4\pi R^2

And since the electric field is perpendicular to the surface at any point, Gauss Law becomes

E\cdot 4\pi R^2 = \frac{q}{\epsilon_0}

The charge included within the sphere in this case is the charge on the paint layer, therefore

q=-17.0\mu C=-17.0\cdot 10^{-6}C

So, the electric field is:

E=\frac{q}{4\pi \epsilon_0 R^2}=\frac{-17.0\cdot 10^{-6}}{4\pi(8.85\cdot 10^{-12})(0.065)^2}=-3.62\cdot 10^7 N/C

where the negative sign means the direction of the field is inward, since the charge is negative.

c)

Here we want to calculate the electric field 8.00 cm outside the surface of the paint layer.

Therefore, we have to take a Gaussian sphere of radius:

r=8.00 cm + R = 8.00 + 6.50 = 14.5 cm = 0.145 m

Gauss theorem this time becomes

E\cdot 4\pi r^2 = \frac{q}{\epsilon_0}

And the charge included within the sphere is again the charge on the paint layer,

q=-17.0\mu C=-17.0\cdot 10^{-6}C

Therefore, the electric field is

E=\frac{q}{4\pi \epsilon_0 r^2}=\frac{-17.0\cdot 10^{-6}}{4\pi(8.85\cdot 10^{-12})(0.145)^2}=-7.27\cdot 10^7 N/C

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
2 years ago
An object of mass m swings in a horizontal circle on a string of length L that tilts downward at angle θ. Find an expression for
VikaD [51]
We know that
g = LcosΘ 
<span>where g, L and Θ are centripetal gravity length, and angle of object
</span><span>ω² = g/LcosΘ </span>
<span>ω = √(g / LcosΘ) </span>
8 0
2 years ago
Read 2 more answers
A 100-N force causes an object to<br> accelerate at 2 m/s/s. What is the<br> mass of the object?
Kitty [74]

Answer:

50\; \rm kg.

Explanation:

By Newton's Second Law, the acceleration a of an object is proportional to the net force \sum F on it. In particular, if the mass of the object is m, then

\sum F = m \cdot a.

Rewrite this equation to obtain:

\displaystyle m = \frac{\sum F}{a}.

In this case, the assumption is that the 100\; \rm N force is the only force that is acting on the object. Hence, the net force \sum F on the object would also be

Make sure that all values are in their standard units. Forces should be in Newtons (same as \rm kg \cdot m \cdot s^{-2}, and the acceleration of the object should be in meters-per-second-squared (\rm m \cdot s^{-2}). Apply the equation \displaystyle m = \frac{\sum F}{a} to find the mass of the object.

\displaystyle m = \frac{100\; \rm N}{2\; \rm m \cdot s^{-2}} = 50\; \rm kg.

4 0
2 years ago
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