An amusement park ride raises people high into the air, suspends them for a moment, and then drops them at a rate of free-fall a
2 answers:
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Answer:
The flux is 682.6 Wb.
Explanation:
Given that,
Vector field
We need to calculate the flux
Using formula of flux
Put the value into the formula
Hence, The flux is 682.6 Wb.
Answer:
E. downward and constant
Explanation:
Freefall is a special case of motion with constant acceleration because the acceleration due to gravity is always constant and downward. This is true even when an object is thrown upward or has zero velocity.
For example, when a ball is thrown up in the air, the ball's velocity is initially upward. Since gravity pulls the object toward the earth with a constant acceleration ggg, the magnitude of velocity decreases as the ball approaches maximum height. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth.
Answer:
See explanation below
Explanation:
As I say in the comments, the question is incomplete, however, I will try to answer this by using data that I found on another site.
This is the part of the question that is not here:
If measurements are recorded to the nearest
tenth of a kilogram, find the fraction of these poodles
with weights
(a) over 9.5 kilograms;
(b) of at most 8.6 kilograms;
So, assuming a mean of 8 kg, and 0.9 of standard deviation, let X represents the weight of the poodles
The expression to calculate the fraction of poodle needed is:
Z = X - u / d
u: weight of the large number of poodle
d: standard deviation
Replacing data of a) wer have:
Z = 9.5 - 8 / 0.9
Z = 1.67
With this value, we need to take the value of Z, and see the area under the curve of standard deviation (see table attached)
Therefore:
P (X > 9.5) = P(Z > 1.67) = 0.5 - P (Z < 1.67) = 0.5 - 0.4525 = 0.0475
b) In this part, is the same as part a) so:
Z = 8.6 - 8 / 0.9 = 0.67
The value for area in the curve is 0.2486 so:
P = 0.5 + 0.2486 = 0.7486
Hope this helps
A. 90.1 m
The wavelength of a wave is given by:
where
v is the speed of the wave
f is its frequency
For the sound emitted by the whale, v = 1531 m/s and f = 17.0 Hz, so the wavelength is
B. 102 kHz
We can re-arrange the same equation used previously to solve for the frequency, f:
where for the dolphin:
v = 1531 m/s is the wave speed
is the wavelength
Substituting into the equation,
C. 13.6 m
Again, the wavelength is given by:
where
v = 340 m/s is the speed of sound in air
f = 25.0 Hz is the frequency of the whistle
Substituting into the equation,
D. 4.4-8.7 m
Using again the same formula, and using again the speed of sound in air (v=340 m/s), we have:
- Wavelength corresponding to the minimum frequency (f=39.0 Hz):
- Wavelength corresponding to the maximum frequency (f=78.0 Hz):
So the range of wavelength is 4.4-8.7 m.
E. 6.2 MHz
In order to have a sharp image, the wavelength of the ultrasound must be 1/4 of the size of the tumor, so
And since the speed of the sound wave is
v = 1550 m/s
The frequency will be