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asambeis [7]
1 year ago
13

Suppose that a rectangular toroid has 2,000 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i

s h = 0.60 m, what is the current (in A) flowing through the rectangular toroid when the energy in its magnetic field is 4.0 ✕ 10−6 J?
Physics
1 answer:
andrey2020 [161]1 year ago
3 0

Answer:

0.01154 A

Explanation:

We have given the energy in the magnetic field U=4\times 10^{-6}J

Value of inductance L =0.060 H

Energy stored in magnetic field is given by U=\frac{1}{2}Li^2

i=\sqrt{\frac{2U}{L}}

i=\sqrt{\frac{2\times 4\times 10^{-6}}{0.06}}=0.01154\ A

So the current flowing through rectangular toroid will be 0.01154 A

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(Double points) A machine receives electricity that enables it to deliver a total of 8,542 N of force for the completion of its
storchak [24]

Answer: machine's efficiency = 82.2%

Explanation:

Efficiency of a machine is the capability of a machine to convert input to output without waste.

It can be expressed as

Efficiency = output/ input × 100%

Output = 7,023N

Imput = 8,542N

Efficiency = 7,023N/8,542N × 100%

Efficiency = 82.2%

4 0
1 year ago
A 5.00-kg ball is hanging from a long but very light flexible wire when it is struck by a 1.50-kg stone traveling horizontally t
devlian [24]

consider the right direction as positive and left direction as negative.

M = mass of the ball = 5 kg

m = mass of stone = 1.50 kg

V_{bi} = initial velocity of the ball before collision = 0 m/s

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V_{bf} = final velocity of the ball after collision = ?

V_{sf} = final velocity of the stone after collision = - 8.50 m/s

using conservation of momentum

MV_{bi} + mV_{si} = MV_{bf} + mV_{sf}

(5) (0) + (1.5) (12) = 5 V_{bf} + (1.50) (- 8.50)

V_{bf} = 6.15 m/s

h = height gained by the ball

using conservation of energy

Potential energy gained by ball at Top = kinetic energy at the bottom

Mgh = (0.5) MV_{bf}^{2}

(9.8) h = (0.5) (6.15)²

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8 0
1 year ago
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A circular coil has a 10.0 cm radius and consists of 30.0 closely wound turns of wire. an externally produced magnetic field of
IrinaVladis [17]
Magnetic flux can be calculated by the product of the magnetic field and the area that is perpendicular to the field that it penetrates. It has units of Weber or Tesla-m^2. For the first question, when there is no current in the coil, the flux would be:

ΦB = BA
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          A = π(.1 m)^2
          A = π/100 m^2   

 ΦB = 2.60x10^-3 T (π/100 m^2 ) ΦB = 8.17x10^-5 T-m^2 or Wb (This is only for one loop of the coil)

The inductance on the coil given the current flows in a certain direction can be calculated by the product of the total number of turns in the coil and the flux of one loop over the current passing through. We do as follows:

L = N (ΦB ) / I
L = 30 (8.17x10^-5 T-m^2) / 3.80 = 6.44x10^-4 mH

6 0
1 year ago
A 40-mH ideal inductor is connected in series with a 50 Ω resistor through an ideal 15-V DC power supply and an open switch. If
sergey [27]

Answer:i=300 mA

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Time constant(\tau)=\frac{L}{R}

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current i_0=\frac{V}{R}

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Current as a function of time is given by

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6 0
2 years ago
The Olympic record for running the 200 m dash is 19.3 seconds. What is the average speed for this record?
Hoochie [10]

Answer:

A

Explanation:

v = change of X / change of T

v = 200/19.3

8 0
1 year ago
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