Answer:
0.6
Explanation:
The volume of a sphere = 
Therefore 
r of the disc = 
Using conservation of angular momentum;
The
of the sphere = 
of the disc = 

= 0.6
Answer:
The friend on moon will be richer.
Explanation:
We must calculate the mass of gold won by each person, to tell who is richer. For that purpose we will use the following formula:
W = mg
m = W/g
where,
m = mass of gold
W = weight of gold
g = acceleration due to gravity on that planet
<u>FOR FRIEND ON MOON</u>:
W = 1 N
g = 1.625 m/s²
Therefore,
m = (1 N)/(1.625 m/s²)
m(moon) = 0.6 kg
<u>FOR ME ON EARTH</u>:
W = 1 N
g = 9.8 m/s²
Therefore,
m = (1 N)/(9.8 m/s²)
m(earth) = 0.1 kg
Since, the mass of gold on moon is greater than the mass of moon on earth.
<u>Therefore, the friend on moon will be richer.</u>
Answer:
The rate of change of the height is - 4 ft/s
Solution:
As per the question:
Height of the person, y = 5 ft
The rate at which the person walks away, 
Distance of the spotlight from the wall, x = 40 ft
Now,
To calculate the rate of change in the height,
of the person when, x = 10 m:
From fig 1.
![\Delta ABC[\tex] ≈ [tex]\Delta PQC[\tex]Thus[tex]\frac{BC}{AB} = \frac{PQ}{QC}](https://tex.z-dn.net/?f=%5CDelta%20ABC%5B%5Ctex%5D%20%E2%89%88%20%5Btex%5D%5CDelta%20PQC%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3EThus%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7BBC%7D%7BAB%7D%20%3D%20%5Cfrac%7BPQ%7D%7BQC%7D)

xy = 200 (1)
Differentiating the above eqn w.r.t time t:

Thus
(2)
From eqn (1):
When x = 10 ft
10y = 200
y = 20 ft
Using eqn (2):
