Answer:
Total Work done =0.65 joule
Explanation:
Work done is given Mathematically as
W=F *d
Where w=work done in joules
F=applied force
d= distance moved
The work done to move the toy accros the first meter is
W1=0.5*1
W1=0.5joule
The work done to move the toy across the next 2m at an angle of 30° is
.W2=0.5*2cos30
W2=0.5*2*0.154
W2=0.154joule
Hence total work done is
W1+W2=0.5+0.154
Total Work done =0.65 joule
The position function x(t) of a particle moving along an x axis is 
a) The point at which particle stop, it's velocity = 0 m/s
So dx/dt = 0
0 = 0- 12t = -12t
So when time t= 0, velocity = 0 m/s
So the particle is starting from rest.
At t = 0 the particle is (momentarily) stop
b) When t = 0
SO at x = 4m the particle is (momentarily) stop
c) We have
At origin x = 0
Substituting
t = 0.816 seconds or t = - 0.816 seconds
So when t = 0.816 seconds and t = - 0.816 seconds, particle pass through the origin.
Answer:
A) having each person listen to just 1 song instead of 5.
Explanation:
Ravi could accurately use the outcome to compare the hearing capacities of his friends by this experiment if appropriate precautions are observed.
Playing 5 well known songs simultaneously could result to the interference of sounds when each participant moves away from the player. Which could naturally cause the variation in volume of the songs played with respect to the increasing distance.
Therefore, the reliability of the result from this experiment can be increased if each person listen to just 1 song instead of 5 at a predetermined volume. Each participant would be able to focus on hearing a song during the experiment.
Answer:
(a) 0.84 s
(b) 8.22 m/s
(c) 15.33 m/s
Explanation:
u = 0 , h = 3.45 m, g = 9.8 m/s^2
Let time taken to reach the water is t and the velocity at the time of hitting of water surface is v.
(a) Use first equation of motion
s = u t + 1/2 a t^2
3.45 = 0 + 0.5 x 9.8 x t^2
t = 0.84 second
(b) Use first equation of motion
v = u + a t
v = 0 + 9.8 x 0.84 = 8.22 m/s
(c) If h = 12 m
use third equation of motion
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 9.8 x 12
v = 15.33 m / s
Answer:
147.45 Hz
Explanation:
v = Speed of sound in water = 1482 m/s
= Speed of whale = 4.95 m/s
The difference in frequency is given by
Frequency of the wave in stationary condition
Ship's frequency which is reflected back
The difference in wavelength is 147.45 Hz
