Density is mass divides by volume, so
89.6g / 10cm^3 =8.96g /cm^3
*cm^3 is a standard unit of volume*
Initially, the energies are:

At final point, the energies are:

Using conservation law of energy,
The equation is further simplified as:

is the best estimate of the density of the air on the planet.
Given:
The mass of the conical flask with stopper is 457.23 grams and the volume is
.
Mass of conical flask and a stopper after removing the air is 456.43 g
To find:
The density of the air on the planet.
Solution;
Mass of the conical flask and stopper with air on the planet= 457.23 g
Mass of conical flask with a stopper and without air on the planet = 456.43 g
Mass of the air in the conical flask on the planet =m

The volume of the conical flask = 
The volume of the air in the conical flask = 

The density of the air on the planet = d

is the best estimate of the density of the air on the planet.
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To solve this question, we need to use the component method and split our displacements into their x and y vectors. We will assign north and east as the positive directions.
The first movement of 25m west is already split. x = -25m, y = 0m.
The second movement of 45m [E60N] needs to be split using trig.
x = 45cos60 = 22.5m
y = 45sin60 = 39.0m
Then, we add the two x and two y displacements to get the total displacement in each direction.
x = -25m + 22.5m = -2.5m
y = 0m + 39.0m
We can use Pythagorean theorem to find the total displacement.
d² = x² + y²
d = √(-2.5² + 39²)
d = 39.08m
And then we can use tan to find the angle.
inversetan(y/x) = angle
inversetan(39/2.5) = 86.3
Therefore, the total displacement is 39.08m [W86.3N]
A sound wave. Because in a vacuum there is no medium in a vacuum. And the only wave that requires a medium to travel through is a sound wave.