Answer:
Final temperature will be 438.076 K
Explanation:
We have given temperature
Volume 
As there is no heat transfer so this is an adiabatic process
For and adiabatic process 
Here 
So 

Answer:
La velocidad angular del niño y del carrusel cuando se mueven juntos es 0.208 radianes por segundo.
Explanation:
Asumamos que tanto el niño como el carrusel no tienen carga externa aplicada sobre aquellos, de modo que se puede aplicar el Principio de Conservación de la Cantidad de Movimiento Angular:
(1)
Donde:
- Masa del niño, medida en kilogramos.
- Velocidad lineal inicial del niño, medida en metros por segundo.
- Radio máximo del carrusel, medida en metros.
- Momento de inercia del carrusel, medida en kilogramo-metros cuadrados.
- Velocidad angular final del sistema niño-carrusel, medida en radianes por segundo.
Si sabemos que
,
,
y
, tenemos que la velocidad angular final es:



La velocidad angular del niño y del carrusel cuando se mueven juntos es 0.208 radianes por segundo.
Answer:
A. 0.432
B. -1.92
C. 1.44 units/second
D. -3.2 units/second
Explanation:
A. To calculate her x position, we just use the following equation of motion to find the distance traveled:

here s = displacement
t = time (in seconds)
a = acceleration
Solving for the distance, we get:

s = 0.432 m
Since 0.432 meters east is equals to 0.432 meter in the positive x-direction, the x position is also 0.432.
B. Since the skater has a constant v - velocity of -3.2 m/s, (south means negative y axis), the total distance traveled is:
Distance = speed * time = -3.2 * 0.6 = -1.92 m
The answer is -1.92 units in the y-axis.
C. The x velocity component is the final speed in the east direction, which is going to be:


v = 1.44 units/second (in positive x direction)
D. Her y velocity component does not change, since the velocity towards the south is a constant 3.2 m/s
Thus the answer is -3.2 units/second in the y-axis.
Answer:
1.17894 m
Explanation:
The rock is at one end of the rod which is 0.211 m from the fulcrum
F = Force
d = Distance
L = Length of rod
M = Mass of rock = 325 kg
g = Acceleration due to gravity = 9.81 m/s²
Torque

Torque of man

Torque of rock

The torques acting on the system is conserved

The length of the rod is 1.17894 m