Answer:
Explanation:
Given:
<u>Now as we know that the value of gravity of any heavenly body is at height h is given as:</u>
∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.
Answer:
The final velocity of the first glider is 0.27 m/s in the same direction as the first glider
The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.
0.010935 J
0.0858675 J
Explanation:
= Mass of first glider = 0.3 kg
= Mass of second glider = 0.15 kg
= Initial Velocity of first glider = 0.8 m/s
= Initial Velocity of second glider = 0 m/s
= Final Velocity of first glider
= Final Velocity of second glider
As momentum and Energy is conserved
From the two equations we get
The final velocity of the first glider is 0.27 m/s in the same direction as the first glider
The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.
Kinetic energy is given by
Final kinetic energy of first glider is 0.010935 J
Final kinetic energy of second glider is 0.0858675 J