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liberstina [14]
2 years ago
11

You throw a Frisbee of mass m and radius r so that it is spinning about a horizontal axis perpendicular to the plane of the Fris

bee. Ignoring air resistance, the torque exerted about its center of mass by gravity is
Physics
1 answer:
Usimov [2.4K]2 years ago
7 0

Answer:

Torque τ =w ×0 = 0

Explanation:

We know that the torque is given by the product of the force and perpendicular distance between the force and the axis.

Here the gravity force act at the center and the rotational axis is also passing through the center.

Therefore the perpendicular distance between the force and the rotational axis would be zero.

Hence the torque will be

Torque = Force × Perpendicular distance

Torque = mg×0 = 0

Therefore the torque would be zero.

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Answer:

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Answer:

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2 years ago
A shot-putter exerts a force of 0.142 kN on a shot, accelerating it to 22.75 m/s2. What is the mass of the shot?
Svetach [21]

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Actually Welcome to the Concept of the Force and Power.

Since, according to the Newton's law,

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2 years ago
All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is
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All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is in a state known as constant velocity. The bullet is moving at a constant value of velocity. Acceleration is the rate of velocity so having zero acceleration would mean that there is no change in velocity per unit of time.<span />
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Answer:

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B. If the lifted index is negative then the parcel temperature is warmer than the actual temperature. In addition, the parcel that is less warm than the surrounding will be less dense and will rise.

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